Y = -5x +18
x can be any number, y can be change due to x value
There are
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's
way of doing that.
So we have
![\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520](https://tex.z-dn.net/?f=%5Cdbinom%7B10%7D2%5Cdbinom83%5Cdbinom55%3D%5Cdfrac%7B10%21%7D%7B2%21%2810-2%29%21%7D%5Cdfrac%7B8%21%7D%7B3%21%288-3%29%21%7D%5Cdfrac%7B5%21%7D%7B5%21%285-5%29%21%7D%3D2520)
The last expression has a more compact form in terms of the so-called multinomial coefficient,
![\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520](https://tex.z-dn.net/?f=%5Cdbinom%7B10%7D%7B2%2C3%2C5%7D%3D%5Cdfrac%7B10%21%7D%7B2%213%215%21%7D%3D2520)
Mean is when you take all the numbers and add them together and divide by the amount of numbers there
Example: Find the mean of :3,4,6,7
So you a 3+4+6+7=20 divide that by 4(because there you added 4 numbers) and that equals 5