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erastovalidia [21]
1 year ago
12

When she subtracts 4 from both sides, Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction x.

results. What is the value of ?
–1
–negative StartFraction one-half EndFraction
0
StartFraction one-half EndFraction.
Mathematics
1 answer:
timama [110]1 year ago
7 0

The value of x in the equation 1/2x = -1/2x when 4 is subtracted from both sides is 0(not defined)

Subtraction of fraction

Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction

1/2x = -1/2x

  • Subtract 4 from both sides

1/2x - 4 = -1/2x - 4

(x-8) / 2 = (-x-8) / 2

(x - 8) / 2 = (-x-8) / 2

  • cross product

2(x - 8) = 2(-x - 8)

2x - 16 = -2x - 16

2x + 2x = -16 + 16

4x = 0

Learn more about fraction:

brainly.com/question/11562149

#SPJ1

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Solve the inequality
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-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
==============================
32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
============================
6y + 1 > = 10
6y > = 10 - 1
6y > = 9
y > = 9/6 which reduces to 3/2 or 1 1/2

-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
y < = -18/3 which reduces to - 6

so y > = 9/6(or 1 1/2) or y < = -6


3 0
3 years ago
Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads
Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

Distance = Speed \times Time

Distance\ OA = 10 \times 2.5 = 25\ km

Distance\ OB = 16 \times 2.5 = 40\ km

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled \triangle AOB.

According to Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km

The speed at which distance is increasing between the two boats is given as:

\dfrac{47.17}{2.5} \approx 18.87\ km/hr

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2 years ago
Naomi wants to take fitness classes at a nearby gym, but she needs to start by selecting a membership plan. With the first membe
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54+x=12+3x
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Solve this problem<br> √-16
a_sh-v [17]

Answer:

4i

Step-by-step explanation:

\sqrt{-1}  = i

Therefore \sqrt{-16} = \sqrt{16} \sqrt{-1} \\=4i

3 0
2 years ago
A triangle has side lengths of ( 5.9 k + 9.3 m ) (5.9k+9.3m) centimeters, ( 3.6 k − 3.9 n ) (3.6k−3.9n) centimeters, and ( 3.5 n
Lilit [14]

Answer:

(9.5k + 12.7m -0.4n) cm

Step-by-step explanation:

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