When she subtracts 4 from both sides, Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction x.
1 answer:
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Answer:
5.78% probability that exactly 2 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smarthphone in meetings or classes, or they do not. The probability of an adult using their smartphone on meetings or classes is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
63% use them in meetings or classes.
This means that
7 adult smartphone users are randomly selected
This means that
Find the probability that exactly 2 of them use their smartphones in meetings or classes.
This is P(X = 2).
5.78% probability that exactly 2 of them use their smartphones in meetings or classes.
Using addition
x-y+1/2x+y=1+5
x+1/2x+0y=6
3/2x=6
3x=12
x=4
Using the value of x
x-y=1
4-y=1
y=3
With x as 4 and y as 3, their product is 12
And can be written as (4,3)
x-y+1/2x+y=1+5
x+1/2x+0y=6
3/2x=6
3x=12
x=4
Using the value of x
x-y=1
4-y=1
y=3
With x as 4 and y as 3, their product is 12
And can be written as (4,3)