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2 years ago

Matrix A has 2 rows and 3 columns whereas matrix B has3 rows and 2 column

Mathematics

1 answer:

sergeinik [125]2 years ago

8 0

Step-by-step explanation:

for any matrix multiplication number of columns of first matrix should be equal to number of rows of second matrix.

For AB

A has 3 columns and B has 3 rows so it matches . Hence can be multiplied.

For BA

B has 2 columns and A has 2 rows it also matches so can be multiplied

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Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744$

99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

7 0

3 years ago

Simplify (-6)^5 how do you simplify the the exponent expression

Papessa [141]

X^m means x times itself m times

(-6)^5 means -6 time itself 5 times
simplify it says
remember that
(mn)^x=(m^x)(n^x)
undistribute the -1
(-6)^5=(-1)^5 times (6^5)
(-1)^5=-1 since it is odd power
can be simplified to
-6^5
(note, -6^5 vs (-6)^5 PEMDAS)

5 0

3 years ago

Read 2 more answers

A: Which expression shows how many ways 7 people can be arranged on individual Ferris wheel seats?

Assoli18 [71]

A: 7! and
<span>B: 5040

you only have 7 slots with 7 * 6 * 5 * 4 * 3 * 2 * 1</span>

8 0

3 years ago

What is the distance between the points? Round to the nearest 10th if necessary

Ulleksa [173]

Step-by-step explanation:

because