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mr_godi [17]
2 years ago
15

Find the least common multiple of 25, 10, and 30.

Mathematics
1 answer:
elena-s [515]2 years ago
8 0

The least common multiple of 10, 25 and 30 is 150.

Hope this helps ! :)

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The sum of two numbers is 72 while the difference between the numbers is 25. the larger of the numbers is
7nadin3 [17]
2 equations:  the first one is the sum of 2 unknown numbers x and y: x + y = 72. Now the difference is 25, so x - y = 25. Solve the first equation for y: y = 72 - x. Sub that into the second equation to solve for x: x - (72 - x) = 25. x - 72 + x = 25 and 2x - 72 = 25.  Therefore, 2x = 97 and x = 48.5  That's the larger of the 2 numbers; since we subtracted y from x we defined x as the larger of the 2.  Just for fun, plug x in to find that y = 23.5
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3 years ago
If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.
Triss [41]
(6y - 11)(6y + 11) = ay² - b    |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b    |add b to both sides

ay² = 36y² - 121 + b        |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

\boxed{a=\dfrac{36y^2-121+b}{y^2}}
7 0
3 years ago
Choose a method 70*55
MissTica
The method is to multiply 
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3 years ago
How do you solve: 2(7-x)+4x=20
Angelina_Jolie [31]
First expand it
Next subtract 14 - 2x + 4x so it can be 14 + 2x
Next subtract 14 from both sides
Next subtract 20 - 14 so it can be 6
Then divide both sides by 2
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5 0
3 years ago
Mrs.gauthier plans to take her class on 2 field trips this year there are 23 students in her class and each field trip will cost
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If there is 2 field trips with 23 students and each student costs $5 dollars. So for the 1st trip it will be 23x$5

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And on the second trip its the same because there is 23 students that cost 5 dollars so it will be 23x5

2nd trip- $115

To find out the total of both trips youd add 115+115/

In total, for both trips it will cost $230 dollars.

7 0
3 years ago
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