Answer:
56
Step-by-step explanation:
Given that there are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom.
The three candidates that receive the highest number of votes become candidates for a runoff election.
i.e. 3 persons out of 8 to be selected for becoming candidates for a runoff election.
Since order does not matter we use combinations here
3 persons out of 8 can be done in 8C3 ways
= 56
no of 3-candidate combinations possible are 56
Answer:
the answer would be 13
Step-by-step explanation:
365×3= 1095
1095+366= 1461
1,461 days.
Old Condition
Numerator = n = x
denominator = d = 2n + 3
New Condition
(x - 1) /(2x + 3 - 1) = 7 / 16
(x - 1) / (2x + 2) = 7 / 16
Cross multiply and solve
16*(x - 1) = 7 * (2x + 2) Remove the brackets.
16x - 16 = 14x + 14 Add 16 to both sides.
16x = 14x + 30 Subtract 14x from both sides.
2x = 30 Divide by 2
x = 15
You really should check this.
Original fraction
15/33
Now subtract 1 from the top and bottom.
14/32 Divide both by 2
7 / 16 which checks out perfectly
Solve for the x-max or h :\
plug it in to equation to get k:/
-8+16+3=11=k
solve for a by pluging (0,0)
then a= -11/4
