All categories

2 years ago

What is the x and y intercept of the parabola y=x^2-6x+10 and ow do you graph the equation

1 answer:

7 0

The x- intercept is where y = 0 on the graph and the y- intercept is where x= 0 on the graph. When X=0, all the terms, except for the constant are equal to zero, thus the y- intercept is the constant. y=10 when x=0. Use the quadratic formula to find the x value where y=0.
x= (-b +or- sqrt(b^2 -4ac))/2a

y=ax^2 +bx +c

The answer for the x- int is imaginary. This happens because 10 is the parabola's minimum value and it never touches the x- axis. y-int is 10

You might be interested in

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

3 0

3 years ago

Choose the congruence theorem that you would use to prove the triangles congruent.

Elena L [17]

Answer:

SAS

Explanation:

Before solving the problem, let's define each of the given theorems:

1- SSS (side-side-side): This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle

2- SAS (side-angle-side): This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

3- ASA (angle-side-angle): This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle

4- AAS (angle-angle-side): This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle

Now, let's check the given triangles:

We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

This means that the two triangles are congruent by SAS theorem

Hope this helps :)

5 0

2 years ago

Read 2 more answers

According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, 62% of graduate

egoroff_w [7]

Answer:

$\frac{31}{50}$

Step-by-step explanation:

percentage of graduates with loan = 62%

total sample = 50

Number of student in the sample with student loan

= (percentage of graduates with loan) x (total sample)

= 62% x 50

= 31

Proportion of student in the sample with student loan = $\frac{31}{50}$

4 0

2 years ago

What are the roots of y=x^2 +25

Lena [83]

Answer:

Its a i just took the test

Step-by-step explanation:

4 0

2 years ago

A rectangle garden has a width that is 8 feet less than twice the length. Find the dimensions if the perimeter is 20 feet

Lana71 [14]

Width = 4ft

Length = 6ft

Explanation:

Let length = l ,

So, width = 2l-8

Perimeter of rectangle = 2x(length + width)

According to the question,

$20ft = 2X(l + 2l-8)\\20ft = 2X(3l -8)\\ 10ft = 3l-8\\18ft = 3l \\ l = 6ft$

Hence,

Width = 4ft

Length = 6ft

6 0

3 years ago