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Aleonysh [2.5K]
3 years ago
5

A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, a

nd B tickets cost $60 each. How many tickets of each type were sold?
Mathematics
1 answer:
Effectus [21]3 years ago
6 0
Let a be the tickets that cost 10 each and b the tickets that cost 60 each. So therefore, a + b = 500 and 10a + 60b = 6000. By substituting the given numbers, a will be equals to 480. So the tickets sold are: 480 tickets for 10 each and 20 tickets for 60 each. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
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A parent function f(x)=4x-5 is transformed to f(x)+3. which statement about the graph of f(x)+3 is true?
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Step-by-step explanation:

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Solving Square Root Worksheet (x - k)^2 Part 3
erastova [34]

Answer:

7. x = -2 +/- 4i\sqrt{5}

8. x = 2 or x = 6

9. x = -2 +/- \frac{\sqrt{26} }{2} i

10. t = -3 +/- \sqrt{35}

Step-by-step explanation:

7. Subtract 320 from both sides: 4(x + 2)^2 = -320

Divide by 4: (x + 2)^2 = -80

Square root both sides: x + 2 = +/- \sqrt{-80}. We need to add the imaginary i to this: +/- \sqrt{-80} = +/- i\sqrt{80} = +/- 4i\sqrt{5}

Subtract 2 from both sides: x = -2 +/- 4i\sqrt{5}

8. Add 18 to both sides: 7(x - 4)^2 = 28

Divide by 7: (x - 4)^2 = 4

Square root both sides: x - 4 = +/- 2

Add 4 to both sides: x = 4 +/- 2  ⇒  x = 2 or x = 6

9. Add 5 to both sides: -2(x + 2)^2 = 13

Divide by -2: (x + 2)^2 = -13/2

Square root both sides: x + 2 = +/- \sqrt{-13/2}. We again need i: +/- \sqrt{-13/2} = +/- i\sqrt{13/2} = +/- \frac{\sqrt{26} }{2} i

Subtract 2 from both sides: x = -2 +/- \frac{\sqrt{26} }{2} i

10. Multiply by 5 on both sides: (t + 3)^2 = 35

Square root both sides: t + 3 = +/- \sqrt{35}

Subtract 3: t = -3 +/- \sqrt{35}

Hope this helps!

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