The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
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Answer:
C. 3
Step-by-step explanation:
-9 * -1/3
= -9/ -3
A negative divided by a negative is a positive
9/3
3
A=xy+yz
A=y*(x+z)
y=A/(x+z)
Answer:
Step-by-step explanation:
h(g(x))
g(x)= 3x + 1
h(3x + 1) = 4(3x + 1) = 12x + 4
Answer:-12 x 12 =- 144.
What you do is multiply regularly then add the negative sign, but if your multiplying 2 negatives it’s a positive answer. I cant help with the Fractions caz I’m not good at them lol .
