Here, DH = HF
x+3 = 3y
x = 3y-3 ----(I)
GH = HE
4x-5 = 2y+3
4x = 2y+8
Substitute value of x,
4(3y-3) = 2y+8
12y-12 = 2y+8
12y-2y = 12+8
10y = 20
y = 2
Now, substitute it in equation 1,
x = 3(2)-3
x = 6-3 = 3
So, your final answer is x=3 & y=2
Answer:
Y=K×X...... equation
When,Y=8 and X=-5
To find the constant (K)
we substitute for K in the equation
8=K×-5
8=-5K divide both sides by -5
8÷-5=-5K÷-5
K=-1.6
Factors of 9: 1; 3; 9
Factors of 36: 1; 2; 3; 4; 6; 9; 12; 18; 36
GCF(9; 36) = 9
Answer:
C) 4/(x+y)²
Step-by-step explanation:
start by expanding so it is written as 2÷(x+y)/(x+y)÷2.
Then rearrange so that it is 2×2/(x+y)×(x+y) or 4/(x+y)²
Answer:
She went to go get the milk
Step-by-step explanation:
wait a minute ...............
