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brilliants [131]
2 years ago
7

What is the slope of the line? y - 4= -7(x-6) Choose 1 answer: 1 А. 7 4. B 7 --7 2 3​

Mathematics
1 answer:
givi [52]2 years ago
3 0

Step-by-step explanation:

the slope is always the factor of x.

in slope intercept form, as well as here in point slope form.

the important thing is that the y term is just brought to a simple positive y form (and not cy with c is different than 1).

and then, what you see on the other side as factor is x is the slope.

here : -7

the other numbers in the equating are irrelevant for the slope. they determine the "offset" of the line from (0, 0).

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PLEASE HELP SOON. i have been stuck on this algebra 1 question for what feels like an eternity can someone please help and soon?
-Dominant- [34]
You are trying to find an x-value for which f(x) = g(x).  At first your choice of x is arbitrary.  In the given table, the first x-value tried was 0 (zero).  For this value of x, f(x) does NOT equal g(x).

Next x was 1.  f(x) and g(x) are even further apart here.  So reject 1 and try 2 instead.  Notice how f(x) and g(x) are closer together now than they were for x=1.

Note that for x=2.5, f(x) and g(x) are even closer together; ony 0.75 separates them.   

Your turn.  Try x=2.4, x=2.3, and so on.  You may have to go in the other direction:  Try x=2.6, x=2.7, and so on.  If f(x) and g(x) are getting closer to one another, you're going in the right direction; if further apart, you're going in the wrong direction.  

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6 0
3 years ago
Please help with step by step. Thank you
o-na [289]

Answer:

  • SU = 2
  • PX = 6 2/3

Step-by-step explanation:

The product of distances to the circle along a secant is the same for all secants intersecting a given point.

a. Secants SW and QT intersect at U. Thus ...

  (UT)(UQ) = (US)(UW)

  (1.5)(4) = (SU)(3)

  SU = (4)(1.5)/3

  SU = 2

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b. Secants PT and PX intersect at P. Thus ...

  (PQ)(PT) = (PR)(PX)

  PX = (PQ)(PT)/PR) = (2.5)(2.5 +4 +1.5)/3 = 20/3

  PX = 6 2/3

4 0
3 years ago
a storeroom 21 feet long, 15 feet wide, and 11 feet high was enlarged to a length of 25 feet and a width of 17 feet. how many cu
xenn [34]
<h2>1210 cubic feet</h2>

Step-by-step explanation:

       Initial dimensions of the storeroom were 21\text{ }ft length, 15\text{ }ft width and 11\text{ }ft height.

       The room is in the shape of a cuboid. Volume of a cuboid = V=l\times b\times h, where l,b,h are the length, width and height of the cuboid.

       So, Volume of storeroom initially = 21\text{ }ft\text{ }\times15\text{ }ft\text{ }\times11\text{ }ft\text{ }=3465\text{ }ft^{3}\text{ }

       Finally, the length was increased to 25\text{ }ft and width to 17\text{ }ft.

       Final volume of storeroom = 25\text{ }ft\text{ }\times 17\text{ }ft\text{ }\times 11\text{ }ft\text{ }=4675\text{ }ft^{3}\text{ }

       Increase in volume = 4675\text{ ft}^{3}-3465\text{ ft}^{3}=1210\text{ ft}^{3}

∴ 1210 cubic feet of storage was added.

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Answer:

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Step-by-step explanation:

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