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HACTEHA [7]
3 years ago
5

Solve: 6(y-5) = 2(10 + 3y)

Mathematics
2 answers:
frozen [14]3 years ago
5 0
Simplifying
6[y + -5] = 2(10 + 3y)

Reorder the terms:
6[-5 + y] = 2(10 + 3y)
[-5 * 6 + y * 6] = 2(10 + 3y)
[-30 + 6y] = 2(10 + 3y)
-30 + 6y = (10 * 2 + 3y * 2)
-30 + 6y = (20 + 6y)

Add '-6y' to each side of the equation.
-30 + 6y + -6y = 20 + 6y + -6y

Combine like terms: 6y + -6y = 0
-30 + 0 = 20 + 6y + -6y
-30 = 20 + 6y + -6y

Combine like terms: 6y + -6y = 0
-30 = 20 + 0
-30 = 20

Solving
-30 = 20

Couldn't find a variable to solve for.

no solution
topjm [15]3 years ago
4 0

Answer:

no solution

Step-by-step explanation:

simplifying

6(y + -5) = 2(10 + 3y)

reorder the terms:

6(-5 + y) = 2(10 + 3y)

(-5 * 6 + y * 6) = 2(10 + 3y)

(-30 + 6y) = 2(10 + 3y)

-30 + 6y = (10 * 2 + 3y * 2)

-30 + 6y = (20 + 6y)

add '-6y' to each side of the equation.

-30 + 6y + -6y = 20 + 6y + -6y

combine like terms: 6y + -6y = 0

-30 + 0 = 20 + 6y + -6y

-30 = 20 + 6y + -6y

combine like terms: 6y + -6y = 0

-30 = 20 + 0

-30 = 20

solving for:

-30 = 20

the left and right sides are not equal, so there isn't any solution!

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In 6 years, Mariya will be as old as Vikram is now. In 2 years, Vikram will be three times older than Mariya. Find their ages no
Damm [24]

Answer:

Mariya is 1 year old

Vikram is 7 years old

Step-by-step explanation:

Here, we want to know the present ages of Mariya and Vikram.

Let the present age of Mariya be M and the present age of Vikram be V

From the question, we are told that in 6 years time, Mariya will be as old as Vikram is now

Thus, mathematically;

M + 6 = V ••••••(i)

Furthermore , in 2 years time Vikram will be 3 time older than Mariya

Mathematically;

( V + 2) = 3( M + 2)

V + 2 = 3M + 6

V = 3M + 6-2

V = 3M + 4 •••••••(ii)

So let’s equate the V

3m + 4 = m + 6

3m -m = 6-4

2m = 2

m = 1

But V = m + 6

V = 1 + 6

V = 7

3 0
3 years ago
How do u write 3:4 and 6:8 as a fraction proportion
faltersainse [42]

3/4=6/8

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3 0
3 years ago
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insens350 [35]
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8 0
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DaniilM [7]

Answer:

c)

Step-by-step explanation:

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6 0
3 years ago
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
3 years ago
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