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HACTEHA [7]
2 years ago
5

Solve: 6(y-5) = 2(10 + 3y)

Mathematics
2 answers:
frozen [14]2 years ago
5 0
Simplifying
6[y + -5] = 2(10 + 3y)

Reorder the terms:
6[-5 + y] = 2(10 + 3y)
[-5 * 6 + y * 6] = 2(10 + 3y)
[-30 + 6y] = 2(10 + 3y)
-30 + 6y = (10 * 2 + 3y * 2)
-30 + 6y = (20 + 6y)

Add '-6y' to each side of the equation.
-30 + 6y + -6y = 20 + 6y + -6y

Combine like terms: 6y + -6y = 0
-30 + 0 = 20 + 6y + -6y
-30 = 20 + 6y + -6y

Combine like terms: 6y + -6y = 0
-30 = 20 + 0
-30 = 20

Solving
-30 = 20

Couldn't find a variable to solve for.

no solution
topjm [15]2 years ago
4 0

Answer:

no solution

Step-by-step explanation:

simplifying

6(y + -5) = 2(10 + 3y)

reorder the terms:

6(-5 + y) = 2(10 + 3y)

(-5 * 6 + y * 6) = 2(10 + 3y)

(-30 + 6y) = 2(10 + 3y)

-30 + 6y = (10 * 2 + 3y * 2)

-30 + 6y = (20 + 6y)

add '-6y' to each side of the equation.

-30 + 6y + -6y = 20 + 6y + -6y

combine like terms: 6y + -6y = 0

-30 + 0 = 20 + 6y + -6y

-30 = 20 + 6y + -6y

combine like terms: 6y + -6y = 0

-30 = 20 + 0

-30 = 20

solving for:

-30 = 20

the left and right sides are not equal, so there isn't any solution!

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Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
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Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

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Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

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WX = \sqrt{4 + 1}

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✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

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Plug in the values

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Let,

Y(2, -4) = (x_1, y_1)

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✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

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Plug in the values

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ZW = 2.24

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

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