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Anton [14]
3 years ago
15

Solve the equation cos(x/2)=cos x+1. What are the solutions on the interval 0°

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

+-pi/3 and pi

Step-by-step explanation:

\cos(x/2)=\pm\sqrt{\dfrac{1+\cos x}{2}}=\cos x +1

Squaring both sides:

\dfrac{1+\cos x}{2}=(\cos x + 1)^2

\dfrac{1+\cos x}{2}=\cos^2x+2\cos x+1

1+\cos x=2\cos^2x+4\cos x +2

2\cos^2x+3\cos x +1 =0

(2\cos x + 1)(\cos x + 1)=0

\cos x = -\dfrac{1}{2}, -1

x= \pm\dfrac{\pi}{3}, \pi

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Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients. The polynomial is x³- 7x² - 6x + 72.

<h3>What is a polynomial?</h3>

Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients(constants who are in multiplication with those variables) and constants with only operations of addition, subtraction, multiplication and non-negative exponentiation of variables involved.

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