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gizmo_the_mogwai [7]
3 years ago
12

Describe a real world situation that is modeled by dividing two fractions or mixed numbers

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0
Hey there!
If you have a granola bar, and you've already eaten half of it and your 4 friends come up to you asking for equal pieces, you'd have to divide 1/2 by 4 to ensure that they each get an equal amount, or 1/8 of the bar.
Hopefully this helps!
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The results of the first 100 students who voted are represented in the table. There are still 50 more students left to vote. Bas
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Answer:

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Answer:

m=0.5 b=1

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M is the increase in value by one square point via b.

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Alex and his friend Kim made a one-gallon pitcher of lemonade because it was so hot. They drank 5 glasses that each help 2 cups
natulia [17]

we know that

4 cups of lemonade = 1 quart

1 gallon of lemonade = 4 quarts

1 gallon of lemonade = 16 cups

Step 1

<u>  find the amount of lemonade that's left expressed in cups</u>

5 glasses * 2 cups = 10 cups  

16 cups - 10 cups = 6 cups.  

There are 6 cups of lemonade left.  

Step 2

<u>  find the amount of lemonade that's left expressed in  quarts:  </u>

4 cups = 1 quart.  

(6 cups divided by 4 cups will equal the quarts.)  

6/4=1.5

6 cups = 1.5 quarts.  

There are 1.5 quarts of lemonade left.  

Step 3

<u>  find the amount of lemonade that's left expressed in gallons  </u>

4 quarts = 1 gallon.  

(1.5 quarts divided by 4 quarts will equal the gallon)  

1.5/4=0.375

1.5 quarts = 0.375 gallon.  

There is 0.375 gallon left of lemonade.

6 0
3 years ago
HELP WITH THESE QUESTIONS PART 2... 1 Question
Lunna [17]

<u>Step-by-step explanation</u> and Answers:

(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

cos =  \frac{adjacent}{hypotenuse} = \frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{\sqrt{10}}{10}

tan = \frac{opposite}{adjacent} = \frac{3}{1} = 3

csc = \frac{hypotenuse}{opposite} = \frac{\sqrt{10}}{3}

sec = \frac{hypotenuse}{adjacent} = \frac{\sqrt{10}}{1} = \sqrt{10}

cot = \frac{adjacent}{opposite} = \frac{1}{3}

7 0
4 years ago
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