First, 5 students and 2 teachers is 7 different people. That means there are 7! Ways they can stand in a line. (7! Means 7x6x5x4x3x2x1)
That is 5040 ways.
Having the teachers on either side with the five students in the middle splits the question. There are 2 ways the teachers could stand (TA on left, TB on right or vice versa). There are 5! Ways to arrange the students in the middle. That is, 120. So combined, there are 2x120 ways to have them lined up with the teachers on either side. 240 ways.
Out of the 5040 ways for all of them to line up, one teacher will be in the middle 3 spaces 3/7 of the time. The second teacher will be on one of the remaining 2 central spaces 2/6 (1/3) of the time. 3/7x1/3 = 1/7. That means 1/7 or 14.29% of the time, the two teachers will occupy two of the three middle slots.
Answer:
0.5 repeating
Step-by-step explanation:
you would simply divide 5 by 9 to find the answer.
Answer:
C > h
Step-by-step explanation:
I just did it one my test haha
Answer:
store b
Step-by-step explanation:
I believe the answer would be (-3,-5).
Place the equations on top of each other and figure out how to cancel out one of the digits to get your answer. Try canceling out 2x. Multiply the entire equation y=x+3 by -2 to contradict the second equation. y=x(-2)+3(-2) then you'd get y=-2x-6. -2x-6 above 2x+1, solve. -2 and 2 cancel out so you're left with -6+1, therefore, y=5. Now that you have your y, you must solve for x. Using substitution to solve the equation (I picked 2x+1) you'd get -5=2x+1. Subtract 1 on both sides. +1-1=0 so that cancels out. -5-1=-6 and you're left with -6=2x. So you subtract 2 on both sides because 2 has the variable, and you are left with x=-3. Therefore, the answer is (-3,-5).
