Solution :
First term, a₀ = -10 .
Common difference of A.P. , d = -8 - (-10) = 2 .
Last term, aₙ = 24 .
We know, last term is given by :
aₙ = a₀ + (n-1)d
24 = -10 + (n-1)×2
2n - 2 = 34
n = 18
Now, sum of series is given by :

Hence, this is the required solution.
Answer:
576 cuboids
Step-by-step explanation:
Let
x -----> the length side of the cube
n -----> number of cuboids that are needed
we know that
The volume of the cuboid is equal to

The volume of the cube is equal to

Find the number of cuboids that are needed

n*24 must be a perfect cube
so
The minimum value that satisfied n to make n*24 a perfect cube is n=576

Answer:
16
Step-by-step explanation:
First you want to plug in all the numbers where the letters are
h ( j + i )- k(5) + h
3 ( 2 + 4 )- 1(5) + 3
After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.
6 + 12 - 1(5) + 3
Then you just follow PEMDAS to solve for the rest
6 + 12 - 5 + 3
18 - 5 + 3
13 + 3
16
Step-by-step explanation:
( 0,-4) that the answer