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damaskus [11]
2 years ago
15

Can you simplify 4+6(3)+2(5 1/2 -1)

Mathematics
1 answer:
Greeley [361]2 years ago
7 0

Answer:

31

5 1/2 - 1 = 4.5

4+ 18= 22

2(4.5) = 9

22+ 9 = 31

Step-by-step explanation:

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If P(x)=x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)
zheka24 [161]
Okay so you do p(x) -q(x) and you get (x)^2-5x hope this helps. (Also hope that trigonometry I'm taking comes through lol)
7 0
3 years ago
Latisha worked for six hours and 45 minutes how should she write that on her time card
AlexFokin [52]

Answer:

Hey there!

6 hrs 45 mins =  405 mins, or 6.75 hours.

Hope this helps :)

8 0
2 years ago
(15)Simplify the expression below. Show your work -(-7y+12)
kotykmax [81]
15. -(-7y + 12) = 7y - 12

16. 1/a = 16/18
      cross multiply
      16a = 18
      a = 18/16 = 9/8

17. 8x - 12 = 4x + 24
      8x - 4x = 24 + 12
      4x = 36
      x = 36/4
      x = 9

18. -6b > 42           4b > -4
       b < 42/-6          b > -4/4
       b < - 7              b > -1
so b < -7 and b > -1

19. 6 more then the product of 8 and n
      6 + 8n

20. 45 = 3b + 69
      45 - 69 = 3b
      -24 = 3b
      -24/3 = b
      -8 = b
6 0
3 years ago
Read 2 more answers
I NEED HELP??? with this math problem?
7nadin3 [17]

Answer:


Step-by-step explanation:

35x + 30 = 22x + 69

<u>-22x  -30    -22x  -30</u>

13x = 39

x=3

6 0
3 years ago
The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approxima
worty [1.4K]

We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.

We are asked to find the percentage of students that are between 14 and 18 years old.

First of all, we will find z-score corresponding to 14 and 18 using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{14-15}{2}

z=\frac{-1}{2}

z=-0.5

Similarly, we will find the z-score corresponding to 18.

z=\frac{18-15}{2}

z=\frac{3}{2}

z=1.5

Now we will find the probability of getting a z-score between -0.5 and 1.5 that is P(-0.5.

P(-0.5

Using normal distribution table, we will get:

P(-0.5

P(-0.5

Let us convert 0.62465 into percentage.

0.62465\times 100\%=62.465\%\approx 62.5\%

Therefore, approximately 62.5\% of the students are between 14 and 18 years old.

8 0
3 years ago
Read 2 more answers
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