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Lostsunrise [7]
2 years ago
7

13. Given AXYZ, select ALL statements that apply.​

Mathematics
1 answer:
crimeas [40]2 years ago
7 0
The answer should be a,b,c & f
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1) The cost of constructing a path 5 m broad inside the boundary of a square lawn at Rs 36.25 per sq. metre is Rs 90625. What is
Svetach [21]

Let , side lawn is a.

Area of boundary is :

A=4\times5\times a\\\\A=20a\ m^2

Now, total cost is given by :

T=20a\times 36.25\\\\90625=725a\\\\a=125\ m

Area left is :

A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2

Price to empty space with turfs is :

P=A'\times 20\\\\P=13125\times 20\\\\P=262500

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.

Hence, this is the required solution.

3 0
3 years ago
Which matrix equation has the solution
leonid [27]

Answer: x=0.6 btw how do you put a picture into a question.

5 0
2 years ago
Answer the question below from I ready
san4es73 [151]
Your answer is going to be the first one: 3^2

6 0
2 years ago
Read 2 more answers
Sphere A is similar to Sphere B. The scale factor of the lengths of the radii of Sphere A to Sphere B is 1 to 4. Sphere A has th
AleksAgata [21]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

3 0
3 years ago
SHOW WORK PLS.<br> y = x ^ 2 - x - 11<br> y = - x - 7<br> solve by substitution!
slava [35]
X^2-x-11=-x-7
X^2-11=-7
X^2=4
X=2 (4 was reduced to 2 after the equation was square rooted)
Pls give brainliest so close to ranking up
3 0
2 years ago
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