The claim made by Kyle is not entirely true and unjustifiable because for the figures or solids to be similar, not only the corresponding sides should have the finite ratio but also the corresponding angles should be equal. Although, the claim depends on the type of quadrilateral.
Step-by-step explanation:
3c + 3s = 12.50
4c + 2s = 10.00
3S = 12.50-3c
s = 4.17 - c
4c + 2 (4.17-c) = 10.00
2c + 8.34 = 10.00
2c = 1.66
chips = 0.83
soda = 3.34
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
To do this, you got to square 256.
The square root of 256 is 16.
Therefore, there are 16 small squares on each edge of the mosaic.
Kinda proof:
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25 squares. Square root is 5. 5 along each edge. My work shares same concept.
Extremely unnecessary proof:
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There are 256 squares, and you can count 16 on each edge. this shows 16 times 16, or 16 squared, which is 256.
