$4.00 is my answer.
3x + 5(3) = 27
3x = 27 - 15
3x = 12
x = 12÷3
x = 4
Y = 9x - 5...the slope here is 9...a parallel line will have the same slope.
y = mx + b
slope(m) = 9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = 9(5) + b
-4 = 45 + b
-4 - 45 = b
-49 = b
so ur parallel line is : y = 9x - 49
y = 9x - 5...slope is 9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/9.
y = mx + b
slope(m) = -1/9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = -1/9(5) + b
-4 = -5/9 + b
-4 + 5/9 = b
-36/9 + 5/9 = b
- 31/9 = b
so ur perpendicular line is : y = -1/9x - 31/9
Answer:
The distance between point M and point L is 8
Step-by-step explanation:
The given points on the coordinate are M = (- 2, 4) and L = (4, - 1)
The formula for determining the distance between two points is expressed as
d = √(x2 - x1)^2 + (y2 - y1)^2
Where
y2 = final value of y = - 1
y1 = initial value of y = 4
x2 = final value of x = 4
x1 = initial value of x = - 2
Therefore,
d = √(4 - - 2)^2 + (- 1 - 4)^2
d = √6^2 + (-5)^2
d = √36 + 25
d = √61 = 8
The answer is: 2y^2-20y+12
