All categories

3 years ago

Domain: Ranges: Zeros: Discontinuities: Asymptotes:

Mathematics

1 answer:

trapecia [35]3 years ago

4 0

Domain: The set of possible values of x

Range: The set of possible values of y

Zeros: The x-intercepts (what value of x is on the x-axis)

Discontinuities: Where the graph stops (and restarts somewhere else)

Asymptotes: The graph cannot cross this line (vertical, horizontal, oblique)

You might be interested in

A plot of land is in the shape of a triangle. If one side is x meters, a second side (5x−3) meters, and a third side is ( 7x −

liubo4ka [24]

Given, the plot is in the shape of triangle.

First side = x meter

Second side = ( 5x-3 )meters

Third side = ( 7x-6 ) meters

Perimeter of triangle is equal to the sum of all the three sides.

Perimeter = $x + (5x-3) + (7x-6)$

Combine like terms by adding all the x terms together and all the constant terms together.

Perimeter = $(x+5x+7x) + ( -3 -6 )$

Perimeter = $13x - 9$ feet ... Answer

3 0

3 years ago

O. Find the domain and range of each of the three restricted functions.

Orlov [11]

The domain and range of the functions sin x, cos x, and tan x will be (-∞, ∞) and [-1, 1], (-∞, ∞) and [-1, 1], and R - (2n + 1)π/2 and (-∞, ∞) respectively.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The three restricted functions are given below.

f(x) = sin (x)

f(x) = cos (x)

f(x) = tan (x)

Then the domain of the three restricted functions will be

The domain of sin x will be (-∞, ∞).

The domain of cos x will be (-∞, ∞).

The domain of tan x will be R - (2n + 1)π/2.

Then the range of the three restricted functions will be

The range of sin x will be [-1, 1].

The range of cos x will be [-1, 1].

The range of tan x will be (-∞, ∞).

The graph is given below.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

4 0

1 year ago

Find dy/dx if y=(4x^2-5x)^8

musickatia [10]

dy/dx = 8(8x - 5)(4x² - 5x )^ 7

differentiate using the ' chain rule '

dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)

= 8(4x² - 5x)^ 7 × (8x - 5)

= 8(8x - 5)(4x² - 5x) $^{7}$

6 0

2 years ago

Read 2 more answers

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

2 years ago

Use the image below to answer the following question. What relationship do the ratios of sin x° and cos y° share? (1 point) A ri

dlinn [17]

Answer:

m 36.606

Step-by-step explanation:

90*sin24

90*0.406

is equal to 36.606

approximately 37

5 0

2 years ago