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Anit [1.1K]
3 years ago
12

Domain: Ranges: Zeros: Discontinuities: Asymptotes:

Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Domain: The set of possible values of x

Range: The set of possible values of y

Zeros: The x-intercepts (what value of x is on the x-axis)

Discontinuities: Where the graph stops (and restarts somewhere else)

Asymptotes: The graph cannot cross this line (vertical, horizontal, oblique)

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Length of rectangle is 2(7z + 3) meters. the width is 5z meters than length perimeter in terms of z please
jeka57 [31]

Answer:

Step-by-step explanation:

Given,

Length (l) = 2(7z + 3) = 14z + 6

Breadth (b) = 5z

Now,

Perimeter of rectangle (P) = 2(l + b)

                                           =2(14z + 6 + 5z)

                                           =2(19z + 6)

                                           =38z + 12

4 0
2 years ago
What is the following is the product of (-x - 7)(3x + 1)?​
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Answer:

-3x^2-22x-7

Step-by-step explanation:

8 0
3 years ago
Please help! will give brainliest for the best helper! or first to answer aka meaning first to help :)
AleksAgata [21]

Answer:

angle 2 = 37º

Step-by-step explanation:

When two lines intersect they make vertical angles, which are angles directly across from another. Vertical angles are always congruent.

4 0
3 years ago
❊ Simplify :
Nataliya [291]
<h3>Need to Do :- </h3>
  • To simplify the given expression .

\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }

\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

5 0
2 years ago
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The table represents a linear function
Feliz [49]

Answer:

3

Step-by-step explanation:

.......................

8 0
2 years ago
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