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WITCHER [35]
2 years ago
6

Answer to these 2 questions pls fast!

Mathematics
1 answer:
I am Lyosha [343]2 years ago
3 0

Step-by-step explanation:

17.

an addition is commutative. that means the sequence of the arguments of the operation does not matter (as long as the arguments are truly the same).

7x + 1 = 1 + 7x

1 = 1

0 = 0

is all true for any and every value of x.

so, yes, that's how I know that the expressions are equivalent.

18.

no, the case of 17 does not apply, because she changed the arguments of the addition (not just the sequence).

to check :

7x + 1 = 1x + 7

6x = 6

x = 1

this is true for exactly one value of x. but definitely not fit every value of x.

and so, these 2 existing are not equivalent. they are 2 different functions with a crossing point.

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Please help me with this, please!!!!!!!!!!!!!!!
DIA [1.3K]
First point (0,1)
x=0, -3*0+2y=2, y=1

second point (2,4)
-3x+2y=2
x=2, -3*2+2y=2, -6+2y=2, 2y=8, y=4

third point (-2, -2)  
x=-2, -3*(-2)+2y=2, 6+2y=2, 2y=-4, y=-2

5 0
4 years ago
(5 + 4 - 2) x (-2) = ? <br> A. -22<br> B. 22 <br> C. 14 <br> D. -15
brilliants [131]

It would actually be -14 because 5+4-2=7 and if you multiply 7 by -2 you get -14

4 0
4 years ago
Read 2 more answers
a broken pipe was leaking water at the rate of 2 gal every 5 min. it took 23 min to stop the leak. how many gallons of water wer
Oliga [24]
Leaking water has the rate of 2 gal per 5 minutes which is the same as :
2 gal ÷ 5 minutes = 0.4 gal/minute
Then we multiply it by the number of minutes which is 23 as follows :
0.4 gal/minute × 23 minutes = 9.2 galons wasted during the 23 minutes
8 0
4 years ago
HELP!!! A cell phone is 132 mm long and 57 mm wide. What is ratio of the width and length in simplest form.
GalinKa [24]

The ratio of width to length in simplest form is 19 : 44

<em><u>Solution:</u></em>

Given that, A cell phone is 132 mm long and 57 mm wide

Length of cell phone = 132 mm

Width of cell phone = 57 mm

We have to find the ratio of width and length in simplest form

\frac{Width}{Length} = \frac{57}{132}\\\\\text{Reduce to lowest terms }\\\\\frac{width}{length} = \frac{57 \div 3}{132 \div 3}\\\\\frac{Width}{Length} = \frac{19}{44}

In ratio form, we know that,

\frac{a}{b} = a : b

Writing in ratio form, we get

Width : length = 19 : 44

Thus the ratio of width to length in simplest form is 19 : 44

6 0
3 years ago
Delta makes 12-volt car batteries. These batteries are known to be normally
blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the sample size n =12 -volt car batteries</em>

<em>Let  'X' be a Random variable in a normal distribution</em>

<em>Given that mean of the normal distribution = 45 months</em>

<em>Given that the Standard deviation of the normal distribution = 8months</em>

<u><em>Step(ii):-</em></u>

Let  X₁ = 3 years = 12 × 3 = 36 months

Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125

Let X₂ = 4 years  = 12 × 4 = 48 months

Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375

<u><em>Step(iii)</em></u>:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

                   = P(Z≤0.375) - P(Z≤-1.125)

                   = 0.5 +A(0.375) - (0.5-A(1.125)

                   = 0.5 + 0.1480 - (0.5 -0.3708)

                  = 0.1480 + 0.3708

                 = 0.5188

<u><em>Final answer:-</em></u>

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

<em />

5 0
3 years ago
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