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2 years ago

You need to buy new soil for your garden. Find the area of the garden. Use the dimensions shown in the picture.

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

3 0

Answer:

95 square meters

Step-by-step explanation:

I am answering this question assuming 19 is the base because it is the longest side on the triangle. (there is no picture provided)

The formula for area of triangle is base * height * 1/2

So 19 * 10 *1/2 is 95.

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A plant cell has length 6.6 times 10 Superscript negative 6 m and width 2.2 times 10 Superscript negative 6 m. What is the ratio

Vinvika [58]

The length/width ratio is 3/1 .

l = 6.6 × 10⁻⁶ m; w = 2.2 × 10⁻⁶ m

l/w = 6.6 × 10⁻⁶ m/2.2 × 10⁻⁶ m = 3/1

8 0

3 years ago

An expression to convert 50 miles per hour to miles per minute is shown.

aev [14]

Answer:

(50 mi/h) (1 h/60 min)

Step-by-step explanation:

6 0

2 years ago

32x - 4 = 4x2 + 60 For the equation shown, choose the description of the solutions.

Furkat [3]

All to one side:

4x^2-32x+64 = 0,

divide by 4:

x^2 -8x + 16 = 0

apply formula or see that it is (x-4)^2!, so only x =4 is a root and it is double.

3 0

2 years ago

Read 2 more answers

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

PLEEEAAAAAASE HELP! What is the answer to this question?

IrinaVladis [17]

Answer:

23 units

Step-by-step explanation:

Perimeter is the sum of side lengths

Let's find the sides first

AB = √(-2- 2)² + (-4+1)² = 5
BC = (2 - (-1)) = 3
CD = √(-1- 2)²+(5-2)² = √18 = 3√2 = 4.24
DE = √(-4 -(-1))²+(2-5)²= √18 = 3√2 = 4.24
AE = √(-4-(-2)²+(2-(-4))²=√40= 2√10 = 6.32

Perimeter is

P = 5 + 3 + 4.24 + 4.24 + 6.32 = 22.8 ≈ 23 rounded to the nearest whole number

7 0

3 years ago