Moanna is invting 6 people to her party each person wants 5 cookies and each box has 12 cookies

The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from

melomori [17]

Answer:

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=0.0785$

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

$\mu_{\hat{p}}=p$

$\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}$

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785$

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=0.0785$

8 0

4 years ago

The graph box linear function f passes through the point (1, -9) and has a slope of 3

Marat540 [252]

9514 1404 393

Answer:

C) 4

Step-by-step explanation:

The point-slope equation of the line is ...

y -k = m(x -h) . . . . . line with slope m through point (h, k)

y +9 = 3(x -1) . . . . . line with slope 3 through point (1, -9)

For y=0 (the 0 of the function), we have ...

9 = 3(x -1)

3 = x -1

4 = x

The x-intercept is (4, 0).

3 0

3 years ago

Write an equation of a line in slope intercept form with the given slope and the y-intercept.

defon

The way you put it is confusing. I'll answer but the way you put it was confusing to me.

7 0

3 years ago

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

Effectus [21]

Answer:

make x→0

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

Replace x→-1

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

Now make x→2

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

5 0

3 years ago

Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?

mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If m∠E = m∠Y and m∠F = m∠X

then

Triangles EFG and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

FE and XY

EG and YZ

GF and ZX

so therefore

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.

From the figure in the attachment , we can conclude that:

m∠E = m∠Y

m∠F= m∠X

m∠G = m∠Z

∴ ΔEFG ~ ΔYXZ ( ΔEFG is similar to ΔYXZ )

Because of the similarity , then:

FE : XY = EG : YZ = GF : ZX

Conclusion:

ΔFG is similar to ΔYXZ.

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

3 0

3 years ago

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