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vredina [299]
2 years ago
9

Find the numerical values of -3|x|+2x-1 if x=-5. PLSSSS HELP

Mathematics
1 answer:
Kisachek [45]2 years ago
3 0

Answer:

26

Step-by-step explanation:

Since x = -5, we can replace x with it's numerical -5, right? The problem tells you that x is equal to -5. So, just replace any x you see with -5.

So in this case,

-3|x|+2x-1

turns into:

-3|(-5)|+2(-5)-1

You can use a calculator or solve it by hand to see what the answer is.

-3|(-5)|+2(-5)-1\\-3(5)+2(-5)-1\\-15+(-10)-1\\-25-1\\-26

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The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than
pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

<u>Let radius of the small sphere = </u>x<u />

<u>As the radius of the large sphere is double the radius of the small sphere:</u>

Then, radius of the large sphere = 2x

To find that how many times is the volume of the large sphere than the small sphere, we will <em><u>divide the volume of large sphere by  volume of small sphere:-</u></em>

For smaller sphere: Radius = x

Volume \ of \ sphere = \frac{4}{3} \pi r^{3}

                             =\frac{4}{3} \pi x^{3}

For larger sphere: Radius = 2x

Volume \ of \ sphere = \frac{4}{3} \pi r^{3}

                             =\frac{4}{3} \pi (2x)^{3}

Now, we will divide volume of the larger by the smaller one:

=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\  \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\  \times\frac{1}{x^{3} }

\frac{4}{3}\pi\   is \ canceled\  by\  \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }

<u>Now, we have</u>

= \frac{8}{1}

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

7 0
3 years ago
Read 2 more answers
Solve the system substitution y= 4x + 1 and 3x+2y =13
strojnjashka [21]

Given :

{\qquad \sf \dashrightarrow  y= 4x + 1 \: –––– \sf \:  (i)}

{\qquad \sf \dashrightarrow   3x + 2y = 13 \: –––– \sf \:  (ii)}

Now, Substituing the value of y in equation (ii) :

{\qquad \sf \dashrightarrow   \: 3x + 2y = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 2(4x + 1) = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 8x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x  = 13 - 2   }

{\qquad \sf \dashrightarrow   \: 11x  = 11   }

{\qquad \sf \dashrightarrow   \: x  =  \dfrac{11}{11}    }

{\qquad \sf \dashrightarrow   \bf \: x  = 1   }

Now, substituting the value of x in equation (i) :

{\qquad \sf \dashrightarrow  y= 4x + 1}

{\qquad \sf \dashrightarrow  y= 4(1) + 1}

{\qquad \sf \dashrightarrow  y= 4 + 1}

{\qquad \bf \dashrightarrow  y= 5}

8 0
2 years ago
What is 11/12 divided by 1/3
max2010maxim [7]

Answer:

Step-by-step explanation:

11/12 ÷ 1/3 = 2 3/4, or 11/2 as a improper fraction

hope this helps

3 0
3 years ago
Read 2 more answers
Determine whether the function below is an even function, an odd function, both, or neither.
Ad libitum [116K]
A function is even if, for each x in the domain of f, f (- x) = f (x). The even functions have reflective symmetry through the y-axis. A function is odd if, for each x in the domain of f, f (- x) = - f (x). The odd functions have rotational symmetry of 180º with respect to the origin.
 f (x) = (x + 5) ^ 2
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 f (-x) = (-x + 5) ^ 2
 f (x) = x ^ 2 - 10x + 25
 the function does not comply with the definitions.
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4 0
3 years ago
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ANSWER ASAP PLEASE
yulyashka [42]

The answer is D, 32pi

The radius is half the diameter, which is 32. The circumference equation is 2\pi r or \pi d

So that gives you 32pi

6 0
3 years ago
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