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Answer:
7k
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Step-by-step explanation:
We are trying to combine like terms with the expression: -k - ( - 8k)
We are pretty much solving it.
Solve:
-k - ( - 8k)
The "- ( -" turns into a plus sign.
So it would look like:
-k - -8k or -k + 8k
Now, you would finish solving
-k + 8k = 7k
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Answer:
-1
Step-by-step explanation:
1.)Reorder the terms:
7(8 + x) = 49
(8 * 7 + x * 7) = 49
(56 + 7x) = 49
2.)Solving
56 + 7x = 49
3.)Solving for variable 'x'.
4.)Move all terms containing x to the left, all other terms to the right.
5.)Add '-56' to each side of the equation.
56 + -56 + 7x = 49 + -56
6.)Combine like terms: 56 + -56 = 0
0 + 7x = 49 + -56
7x = 49 + -56
7.)Combine like terms: 49 + -56 = -7
7x = -7
8.)Divide each side by '7'.
x = -1
9.)Simplifying
x = -1
Hope this helps
plz like and brainy
Answer:
okay can you l ike send rge question maybe can solve for it because i don't understand that not to be rude
Answer: actually its 4
Step-by-step explanation:
Answer:
To solve the system below by substitution, replace y in the second equation with 7−6x.
==> False
This statement is false. To solve the system by substitution, replace x in the second equation with 7−6x.
==> False.
This statement is false. To solve the system by substitution, replace y in the first equation with 7−6x.
==> False
This statement is false. To solve the system by substitution, replace y in the second equation with 6x−7.
==> True.
<em>From</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>equat</em><em>ion</em><em>,</em><em> </em><em>6</em><em>x</em><em>-</em><em>y</em><em>=</em><em>7</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>y</em><em>=</em><em> </em><em>6</em><em>x</em><em>-</em><em>7</em>