<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y

0=b+1-c --- equation 2
According to multiple rule of Differentiation,

so, we get



By putting value of point A and putting value of eq 2 we get


Hence proved that the gradient of the curve at A is 1.
Answer:
Step-by-step explanation:
Ive already explained this somebody else asked if you find it you will have the answer
15.69 because 49.57-2.50 divided by 3 =15.69
Answer:
2a
Step-by-step explanation:
using distance formula:
√(x₂-x₁)² + (y₂-y₁)²
putting values,
√{a-(a)}² + {b-b}² = √ {a+a}² + 0²
= √(2a)² = √4a² = 2a
Hope this helps:)