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3 years ago

What are the real zeros of the function g(x)=x^3+2x^2-x-2

1 answer:

4 0

$g(x)=x^3+2x^2-x-2\\\\\text{The zeros:}\\\\g(x)=0\to x^3+2x^2-x-2=0\\\\x^2(x+2)-1(x+2)=0\\\\(x+2)(x^2-1)=0\iff x+2=0\ \vee\ x^2-1=0\\\\x+2=0\ \ \ |-2\\x=-2\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt{1}\to x=-1\ \vee\ x=1\\\\\text{Answer:}\ x=-2\ or\ x=-1\ or\ x=1$

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Help please. I'm stuck

jok3333 [9.3K]

Answer:

The numbers are 65, 67, and 69

Step-by-step explanation:

Hi there!

We need to find 3 consecutive odd integers.

Consecutive numbers are numbers that follow each other (ex. 1, 2, 3, 4)

We're given that 5 times the first number + 4 times the second + 3 times the third = 800

Let's make the first number x

Since the second number is consecutive to the first and odd, it will be x+2 (Why? Well, let's say x is 5. In that case, x+1=6, which is even. However, x+2=7)

Therefore, the third number is x+4 (once again, if x is 5, x+3=8, but x+4=9)

5 times the first number is 5x

4 times the second is 4(x+2)

3 times the third is 3(x+4)

And of course, that equals 800

As an equation, it'll be:

5x+4(x+2)+3(x+4)=800

open the parenthesis

5x+4x+8+3x+12=800

combine like terms

12x+20=800

Subtract 20 from both sides

12x=780

Divide by 12 on both sides

x=65

The first number is x, so the first number is 65

The second number is x+2, or 65+2=67

The third number is x+4, or 65+4=69

Hope this helps!

8 0

3 years ago

I need help pls due in like 5 min

Anni [7]

Answer:

input

Step-by-step explanation:

input is when you put something in to the function

7 0

3 years ago

Put -2, 33, -33, -100, -101, -99, 0, -1, 1, 100, 99 and 25 in order from greatest to least.

gregori [183]

101, 100, 99, 33, 25, 2, 1, 0

You put the same numbers by accident

3 0

3 years ago

9x^8 y^2 - 6x^3 y^4 / 3xy simplified

liberstina [14]

Answer:

None of the choices are correct

Stefofp-by-step explanation:

Simplify the following:

(-6 x^3 y^4 + 9 x^8 y^2)/(3 x y)

Factor 3 x^3 y^2 out of -6 x^3 y^4 + 9 x^8 y^2:

(3 x^3 y^2 (-2 y^2 + 3 x^5))/(3 x y)

(3 x^3 y^2 (-2 y^2 + 3 x^5))/(3 x y) = 3/3×(x^3 y^2 (-2 y^2 + 3 x^5))/(x y) = (x^3 y^2 (-2 y^2 + 3 x^5))/(x y):

(x^3 y^2 (-2 y^2 + 3 x^5))/(x y)

Combine powers. (x^3 y^2 (-2 y^2 + 3 x^5))/(x y) = x^(3 - 1) y^(2 - 1) (-2 y^2 + 3 x^5):

x^(3 - 1) y^(2 - 1) (-2 y^2 + 3 x^5)

3 - 1 = 2:

x^2 y^(2 - 1) (-2 y^2 + 3 x^5)

2 - 1 = 1:

Answer: x^2 y (-2 y^2 + 3 x^5)

6 0

2 years ago

Tara wants to fix the location of a mountain by taking measurements from two positions 3 miles apart. From the first position, t

Black_prince [1.1K]

Answer:

Shortest distance from the mountain is 3.17 miles.

Step-by-step explanation:

From the figure attached,

Let a mountain is located at point A.

Angle between the mountain and point B (∠B) = 53°

Angle between the mountain and point C (∠C) = 78°

Distance between these points = 3 miles

Since, m∠A + m∠B + m∠C = 180°

m∠A + 53° + 78° = 180°

m∠A = 180°- 131° = 49°

By applying sine rule in triangle ABC,

$\frac{\text{sin}(49)}{BC}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}$

AC = $\frac{3\text{sin}(53)}{\text{sin}(49)}$

AC = 3.17 miles

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(78)}{AB}$

AB = $\frac{3\text{sin}(78)}{\text{sin}(49)}$

AB = 3.89 miles

Therefore, shortest distance from the mountain is 3.17 miles.

7 0

3 years ago