By using bodmas you can solve those problems
Look at it as the rise/run. Go up positive 2 on the graph(y-axis) for every 5 that you go across on the graph. Over 5, up 2, over 5, up 2. Hope this helps
Answer:
1/4
Step-by-step explanation:
Just divide the paper that is 1 by 4.
H(x)=-5(x 1/2)^2+5/4 Or X1=0,x2=1
Answer:

Step-by-step explanation:
we know that
The area of a regular hexagon is the same that the area of 6 equilateral triangles
The area of 6 equilateral triangles applying the law of sines is equal to
![A=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
where
b is the length side of the regular hexagon
we have

substitute
![A=6[\frac{1}{2}(10)^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%5E2sin%2860%5Eo%29%5D)
