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ANEK [815]
3 years ago
13

Help please this is due today h(x) = -5x^2 +5x

Mathematics
1 answer:
avanturin [10]3 years ago
5 0
H(x)=-5(x 1/2)^2+5/4 Or X1=0,x2=1
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Choose one of the following people and write about how he or she showed loved for god and others: Dorothy day, saint pio of piet
Murljashka [212]

Answer:

They wanted things done a certain way.

Step-by-step explanation:

When you imagine something in your head you think of it and when it actually happens you want it to be just like you imagined it. In order to have it just the way that you want it you have to have rules so that it would stay just as you wanted it. If something were messed up or done wrong while farming that could cause a time where they go with out and there could be hard time where some people go without food if even one little thing is done wrong.

7 0
3 years ago
Determine the domain of the relation.<br> {(3.0), (2,8), (17,10)}
Trava [24]

Answer:

work is pictured and shown

3 0
3 years ago
Find the area of the shaded region.
DedPeter [7]

Answer:

60+4.5pi

Step-by-step explanation:

6×10 obv + area of circle pi(r^2) and half that for a semi cirxle

3 0
3 years ago
Read 2 more answers
A balloon is blowing up at a constant rate of 9 cubic centimeters per second. When the volume of the balloon is 2048/3 pi cubic
jekas [21]

Answer:

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

Step-by-step explanation:

<u>Rates of Change as Derivatives</u>

If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

\displaystyle V'=\frac{dV}{dr}

The volume of a sphere of radius r is

\displaystyle V=\frac{4}{3}\pi r^3

The volume of the balloon is growing at a rate of 9\ cm^3/sec. This can be written as

\displaystyle \frac{dV}{dt}=9

We need to compute the rate of change of the radius. Note that both the volume and the radius are functions of time, so we need to use the chain rule. Differentiating the volume with respect to t, we get

\displaystyle \frac{dV}{dt}=\displaystyle \frac{dV}{dr}\displaystyle \frac{dr}{dt}

\displaystyle \frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}

solving for \displaystyle \frac{dr}{dt}

\displaystyle \frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2}

We need to find the value of r, which can be obtained by using the condition that in that exact time

\displaystyle V=\frac{2048}{3}\pi\ cm^3

\displaystyle \frac{2048}{3}\pi=\frac{4}{3}\pi r^3

Simplifying and isolating r

\displaystyle r^3=512

\displaystyle r=\sqrt[3]{512}=8\ cm

Replacing in the rate of change

\displaystyle \frac{dr}{dt}=\frac{9}{4\pi 8^2}

\displaystyle \frac{dr}{dt}=\frac{9}{256\pi }

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

8 0
3 years ago
Find the 30th term of the geometric sequence 100, 80, 64,...
Zinaida [17]

Answer:

0.155

Step-by-step explanation:

nth term of a geometric sequence = ar^n-1

Where,

a = first term

r = common ratio

n = number of terms

Given:

100, 80, 64,...

a = 100

r= 80/100

= 4/5

30th term of a geometric sequence = ar^30-1

= ar^29

= 100 × (4/5)^29

= 100 × (0.8)^29

= 100 × 0.00155

= 0.155

Therefore,

30th term of the geometric progression = 0.155

5 0
4 years ago
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