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The general equation of a horizontal ellipse is
(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.
If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,
2b = 16
b = 8
b^2 = 64
The distance between the two foci is 2c. Thus,
2c = 12
c = 6
c^2 = 36
Then, a2 = 64 + 36 = 100. Substituting to the general equation:
x^2/100 + y^2/64 = 1
Answer:
The answer to your question is below
Step-by-step explanation:
9)
They are supplementary angle. The sum of supplementary angles is 180°.
b + 50 = 180
-Solve for b
b = 180 - 50
b = 130°
10)
They are vertical angles. Vertical angles measure the same
b = 43°
11)
They are vertical angles. Vertical angles measure the same.
b = 73°
12)
They are supplementary angles. The sum of supplementary angles is 180°
b + 35 = 180
-Solve for b
b = 180 - 35
b = 145°
X = girls
y = boys
z = students in the bus
x + y = z
x + y = 36
total girls = 2 * total boys
x = 2 * y
2y + y = 36
3y = 36
y = 12
x = 2y = 24 (B)
We have the sequence 2, 6, 10, 14, 18, ... Always 4 being added, so we can say:
The first term is 2. The added is 4, so,
a1 = 2
Prove:
Answer:
5,3,5 range -1,6,2 domain
