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svlad2 [7]
2 years ago
10

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics
2 answers:
Sunny_sXe [5.5K]2 years ago
6 0

Answer:

58

Step-by-step explanation:

upper quartile is the median of the upper half of a data set

The median is the middle number which is 37

There are 5 numbers left in the upper half

The middle number or median  of the upper half is 58

Phantasy [73]2 years ago
4 0
The answer would be 58.
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Square root of 476 is?
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The square root of 476 is 21.8

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3 years ago
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Determine the circumference of<br>a circle with diameter 28 cm. Show your work​
gulaghasi [49]

Answer:

Step-by-step explanation:

Diameter = 28 cm

therefore, radius = 28 / 2 = 14 cm

Circumference = 2 π r

= 2 × 22 / 7 × 14

= <u><em>88 cm</em></u>

Hope this helps

plz mark as brainliest!!!!!

8 0
3 years ago
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Can you help me wit this?
Darya [45]

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2 years ago
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Multiply. Write your answer as a fraction in simplest form. 10/7 x 3/5
ziro4ka [17]
10/7*3/5: 30/35 or 6/7
6 0
2 years ago
I've been having problems with this for a while...
Rina8888 [55]
Like all problems that involve images within the question, we should definitely try to draw this out. In the picture above, I have done this.

Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:

20 ............2.5
-------- = ---------
...x ............. 2

where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:

20×2 = 2.5 × x

Then, to solve for x, we would divide both sides by 2.5. (If you don't know why that is, please let me know and I'll elaborate).

We would then have:

20×2
------- = x
2.5

Which then simplifies to:

x = 16

Try using the same logic for your second question, and if you get stuck, I'd be happy to help! please let me know if any of this doesn't make sense. :)

3 0
3 years ago
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