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Sever21 [200]
3 years ago
10

two rooms in a tiny house share a wall. The area of the bathroom is 24 square ft. The area of the closet is 16 square ft. The ex

pression 24+16 represents the total area in square feet. When two rectangles have a common side, the areas of the rectangles have a common factor. The greatest common factor (GCF) is the greatest factor two or more numbers have in common. What is the greatest common factor (GCF) of 24 and 16?​
Mathematics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

  • 8

Step-by-step explanation:

<u>Factorize each number:</u>

  • 24 = 2*2*2*3
  • 16 = 2*2*2*2

<u>The greatest common factor is:</u>

  • GCF(24,16) = 2*2*2 = 8
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AlladinOne [14]

Answer:

9.50 + 0.20e = 12.50

Step-by-step explanation:

you start with the 9.50, base price. Then with every photo you pay 0.20, since we don't know how many it is we put a variable. Then we know that those two combined is 12.50, so yeah.

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3 years ago
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A scale drawing for the floor of a rectangular office shows the floor to be 33 feet long and 24 feet wide. The business wants to
Fynjy0 [20]

Answer:

C. 7.15 cm

Step-by-step explanation:

step 1

Find the new length of the floor

Remember that

100\%+30\%=130\%=130/100=1.30

The new length is equal to the original length multiplied by 1.30

so

33(1.3)=42.9\ ft

step 2

Find the  length of the floor on the new scale drawing

we have that

The scale drawing is

\frac{1}{6}\ \frac{cm}{ft}

That means

1 cm in the drawing represent 6 feet in the actual

Multiply the length of the floor in the actual by the scale drawing

so

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4 years ago
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Natalija [7]

Answer:

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Step-by-step explanation:

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3 years ago
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Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

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By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

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6 0
4 years ago
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Answer:

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Step-by-step explanation:

Given

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Divide both sides by 5x

5x + 1 = Width

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5 0
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