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Papessa [141]
2 years ago
15

Which list represents the independent values on this graph? 0, 100, 250, 200, 300, 350, 400, 500, 650, 700, 750 1, 2, 3, 4, 5, 6

, 7, 8, 9, 10 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000 1, 100, 2, 250, 3, 200, 4, 300, 5, 400, 6, 350, 7, 500, 8, 650, 9, 700, 10, 750 Scatter plot titled Money in Savings. The horizontal axis is labeled time open parenthesis months close parenthesis, and goes from 0 to 10. The vertical axis is labeled Savings parenthesis dollar sign close parenthesis, and goes form 0 to 1000 in increments of 100. Points plotted are 1 comma 100, 2 comma 250, 3 comma 200, 4 comma 300, 5 comma 400, 6 comma 350, 7 comma 500, 8 comma 650, 9 comma 700, and 10 comma 750.
im sorry its like this i have no idea how to format it



PLEASE HELP ASAP
Mathematics
1 answer:
worty [1.4K]2 years ago
8 0

A scatter plot is used to relate the dependent and the independent values

The list of independent values is:1, 2,3, 4,5,6,7,8,9,10

<h3>How to determine the independent values</h3>

The ordered pairs on the scatter plot are:

(x,y) = (1, 100), (2,250) , (3,200) , (4,300), (5,400), (6,350), (7,500) , (8,650) , (9,700) and (10,750).

Remove the y values

x = 1, 2,3, 4,5,6,7,8,9,10

The x values represent the independent values

Hence, the list of independent values is:1, 2,3, 4,5,6,7,8,9,10

Read more about scatter plots at:

brainly.com/question/6592115

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What’s the value of Y? <br> What’s the measure of angle A? <br> What is the measure of arc DAB
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4 0
2 years ago
Need help in number 12 and 13 PLEASEE!! I don’t get it and I start school the day after tomorrow
Natasha_Volkova [10]

Answer:

The explanations for the graphs are provided down below. Please let me know if you have any questions about my answer.

12 and 13 as written on the worksheet is right.

Step-by-step explanation:

12) The answer given is correct.

The relation between x and y is given as:

y=\frac{x^2}{2}-3 with x \in \{-4,-2,0,2}.

I replaced the word domain with x since the domain is the set of x's for which the relation exists.

We are going to replace x with each of the x's given to see what y corresponds to each.

Let's begin with x=-4.

y=\frac{x^2}{2}-3 with x=-4:

y=\frac{(-4)^2}{2}-3

y=\frac{16}{2}-3

y=8-3

y=5.

So (-4,5) is an ordered pair that should be on our graph.

To find this point you move left 4 from origin then up 5. Now you put a dot where you have landed. Your graph does show this point.

Moving on.

Let's do the next x: x=-2.

y=\frac{x^2}{2}-3 with x=-2:

y=\frac{(-2)^2}{2}-3

y=\frac{4}{2}-3

y=2-3

y=-1.

So (-2,-1) is an ordered pair that should be on our graph.

To find this point you move left 2 from origin and then down 1.  Now you put a dot where you have landed. Your graph shows this point as well.

Now x=0.

y=\frac{x^2}{2}-3 with x=0:

y=\frac{0^2}{2}-3

y=\frac{0}{2}-3

y=0-3

y=-3

So (0,-3) is an ordered pair that should be on our graph.

To find this point you move left and right none and down 3.  Now you put a dot where you have landed. Your graph shows this point.

Now the last point will be at x=2.

y=\frac{x^2}{2}-3 with x=2

y=\frac{2^2}{2}-3

y=\frac{4}{2}-3

y=2-3

y=-1.

So (2,-1) is an ordered pair that should be on our graph.

To find this point you move 2 units right from the origin and then down 1 unit. Now put a dot where you landed.  The graph shows this point as well.

13) The answer given is correct.

g(x)=|x| is the parent function and makes like a V shaped graph where it's vertex is at (0,0).

If we want to move this graph right 3 it becomes:

m(x)=|x-3| \text{ or } m(x)=|(-1)(-x+3)|=|-1||-x+3|=1|-x+3|=|-x+3|=|3-x|.

If you move that up once it becomes:

n(x)=|x-3|+1 or n(x)=|3-x|+1 which is the curve given.

If you don't know about transformations you can choose a few points to plug in to see what's going on with the graph.

Let's choose x=-5,-3,-1,0,1,3,5.

x=-5

f(-5)=|3--5|+1=|3+5|+1=|8|+1=8+1=9.

There is no room for (-5,9) on our graph but if you extended the left hand side of the absolute value function there you would see that (-5,9) is reached.

x=-3

f(-3)=|3--3|+1=|3+3|+1=|6|+1=6+1=7.

(-3,7) should be a point on the graph. Same thing for this point as (-5,9).

x=-1

f(-1)=|3--1|+1=|3+1|+1=|4|+1=4+1=5.

(-1,5) is located on the graph.

x=0

f(0)=|3-0|+1=|3|+1=3+1=4.

(0,4) is also located on the graph.

x=1

f(1)=|3-1|+1=|2|+1=2+1=3.

(1,3) is located on the graph.

x=3

f(3)=|3-3|+1=|0|+1=0+1=1.

(3,1) is located on the graph.

x=5

f(5)=|3-5|+1=|-2|+1=2+1=3.

(5,3) is located on the graph.

Now if we weren't given the graph already:

I would plot the points I found which were:

(-5,9)

(-3,7)

(-1,5)

(0,4)

(1,3)

(3,1)

(5,3)

We should get a basic idea of what the function looks like from these points.

I will graph them. You will have to connect these points because the domain isn't discrete like number 12 is.  That is they didn't list out elements for the domain.

I'm going to graph one more point after x=5.

How about x=7?

f(7)=|3-7|+1=|-4|+1=4+1=5

So (7,5) is also a point on the graph.

You should see that the blue points are following the red path I made there.

8 0
3 years ago
NEED SOMEONE TO CHECK AND TELL ME C
erik [133]
Part A:
f(x)=30(1.2)^x
f(x)=45+3x

Part B: Neighborhood A is 74.6496, so that rounds to 75 homes, and Neighborhood C is exactly 60 homes

Part C:
i would graph them in a graphing calculator, and use the functions to see where the 2 lines intersect.

The x value for when they intersect (# of years) is 3.3207883, so approx. 3.3 years for them to be equal
6 0
3 years ago
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