Answer:
"0.053457 M" of sulfuric acid.
Explanation:
The given values are:
= 10 mL solution
= 12.20 mL
= 22.20 mL
then,
M 0.103 M of NaOH,
= experiment will not be affected
= 10.38 mL
Now,
⇒ mol of NAOH = MV
=
=
Whether Sulfuric acid, then
⇒
⇒
⇒
Before any dilution:
⇒
(Sulfuric acid)
Answer : The option (d) is not a conjugate acid-base pair.
Explanation :
According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.
Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.
(a) The equilibrium reaction will be,
In this reaction, are act as a conjugate acid-base.
(b) The equilibrium reaction will be,
In this reaction, are act as a conjugate acid-base.
(c) The equilibrium reaction will be,
In this reaction, are act as a conjugate acid-base.
(d) The equilibrium reaction will be,
In this reaction, are act as a conjugate base-acid.
Hence, from this we conclude that, the option (d) is not a conjugate acid-base pair but it is a act as conjugate base-acid.