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Rama09 [41]
4 years ago
14

Betsy drives at 10 m/s on an entrance ramp and enters a highway where she increases her speed to 24 m/s in only 3 seconds. What

was Betsy's acceleration?
Chemistry
1 answer:
hjlf4 years ago
3 0
It is 14 m/s

......

............

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Is AgNO3 soluble or insoluble in water?
gtnhenbr [62]

Answer:

Silver Nitrate is very soluble in water.

5 0
3 years ago
Let this be an easy 5 points for your brainly account all is ask for in return is a "thank you"
Svet_ta [14]

Answer:

The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is<u> 14 neutrons</u>

Explanation:

Symbol of Si isotope

_{14}^{28}\textrm{Si}

<u>Number of Neutron = Mass number - Atomic Number</u>

Mass number = Total number of protons and neutrons present in the nucleus of the atom.For Si = 28 amu

Atomic Number = Total number of Protons present in the nucleus.

Si = 14

Number of neutron = 24 - 14

                                = 14

4 0
3 years ago
How many atoms of San are in 0.796 moles of this element
xenn [34]

Answer:

4.8× 10²³ atoms

Explanation:

Given data:

Number of moles of San element = 0.796 mol

Number of atoms present = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.796 mol ×  6.022 × 10²³ atoms / 1mol

4.8× 10²³ atoms

8 0
3 years ago
What is the volume of 1.60 grams of O2 gas at STP? (5 points)
tiny-mole [99]

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
  • 22.4 L x 0.05 = <u><em>1.12 L</em></u>
5 0
2 years ago
Read 2 more answers
Which of the following is evidence of a chemical change?
krek1111 [17]
<span>the formation of a gas
</span>
5 0
3 years ago
Read 2 more answers
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