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bixtya [17]
3 years ago
10

Calcium nitrate reacts with sodium phosphate to form sodium nitrate and calcium phosphate. Given 96.1 grams of calcium nitrate w

hat’s the theoretical yield of calcium phosphate
Chemistry
1 answer:
Bingel [31]3 years ago
5 0
Equation is:

Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2

Balance it out

3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2

You have 96.1g of Calcium Nitrate

Moles = Mass/Molar Mass

Molar mass of Calcium Nitrate is 164.088 g/mol

96.1g / 164.088 g/mol =0.586 moles

Mole ratio is 3:1

Therefore 0.586/3 moles of calcium phosphate

Moles x molar mass = mass

0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
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If one adds 0.1 mol of the weak acid hf (pk_a = 3.2) to a solution with a ph = 2, which species would be most abundant and how m
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F^{-} is most abundant and 6310 times more than HF.

<h3>What is a strong and weak acid?</h3>

When an acid is dissolved in water, all of its molecules disintegrate, making the acid powerful.

When an acid is dissolved in water, only a small number of its molecules disintegrate, making the acid weak. Strong acids have a lower pH than weak acids.

The powerful acids include perchloric acid, chloric acid, nitric acid, sulfuric acid, hydrobromic acid, and hydroiodic acid.

Given:

Pka=3..2

pH=7

Let the volume be 1 liter

[HF]=01 M

pH=pka+log \frac{F^{-}}{HF} \\\\7=3.2+log\frac{F^{-}}{HF} \\3.8=log\frac{F^{-}}{HF}\\ \frac{F^{-}}{0.1}=10^{3.8} \\F^{-}=630.95 M

Now,

\frac{F^{-}}{HF}=\frac{630.95}{0.1}\\ =6309.57

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Therefore, the most abundant is F^{-}and has 6310 times more than HF is F^{-}.

To know more about strong and weak acids, visit: brainly.com/question/12811944

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