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lianna [129]
2 years ago
6

1. y=900(1.27)^x

Mathematics
1 answer:
Sophie [7]2 years ago
7 0

Answer:

The initial value is 900

It is experiencing exponential growth by 27%

Step-by-step explanation:

Exponential functions are in the form y=a(b)^x, where a is the initial value, b is the multiplier, and x is the input, such as how many years past a certain date.

Exponential growth is when the multiplier is above 1.00, or above 100%, because b is determined by 1 + r if you have exponential growth, or 1 - r if you have exponential decay. You will never use negatives with exponential decay.

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Find x<br><br> plz help!!!!!!!!
kompoz [17]
<span>'x' can be anything.  There's no information here to say that it must be
one thing or another. You can't find 'x', because there is no equation.

You can probably simplify the fraction by doing some factoring, but there's
no way to tell a value for 'x'.  As long as 'x' is not -4, it can be anything, and
its value determines the value of the fraction.</span>
7 0
4 years ago
Read 2 more answers
Find the missing term. () + (7 − 3i) + (5 + 9i) + 13i = 10 − 5i.
kotegsom [21]
X + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i

Subtract 13i from both sides

x + (7 -3i) + (5 + 9i) = 10 - 18i

Subtract (5 + 9i). MAKE SURE YOU SUBTRACT 9i TOO. In other words, distribute the negative and subtract 5 and 9i at the same time.

x + (7 - 3i) = 5 - 27i

Do the same with (7 - 3i). You'll be adding 3i since -(-3i) = 3i.

x = -2 - 24i
5 0
4 years ago
Read 2 more answers
What are the minimum and maximum distances that Morgan’s dog may be from the house? (Algebra ll) *URGENT*
Mashcka [7]

Given:

The minimum and maximum distance that the dog may be from the house can be found by using the equation:

|x-500|=8

To find:

The minimum and maximum distance that the dog may be from the house.

Solution:

We have,

|x-500|=8

It can be written as:

x-500=\pm 8

Adding 500 on both sides, we get

x=500\pm 8

Now,

x=500+8 and x=500-8

x=508 and x=492

The minimum distance is 492 meters and the maximum distance is 508 meters.

Therefore, the correct option is C.

6 0
3 years ago
The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0
STatiana [176]

Answer:

The marginal-revenue equation is R'(x)=0.1226x+1.1584.

The marginal revenue for the production of 200,000,000 bushels is R'(x)=1.4036.

The marginal revenue for the production of 650,000,000 bushels is R'(x)=9.1274.

Step-by-step explanation:

The derivative R'(x) of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, R(x) = 0.0613x^{2} +1.1584x+2.4813. Therefore, the marginal revenue function is

R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274

3 0
3 years ago
ILL MARK BRAINLIEST, PLZ HELP ME ASAP!!!!!!!!!!
siniylev [52]
The answer is left 4 and right 3 units hope this helps
7 0
3 years ago
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