Answer:
21 days
Step-by-step explanation:
HETY is a parallelogram.
HT and EY are diagonals. We know that diagonals divides the parallelogram into two equal parts.
So ar(HET) = ar(HTY)
And, ar(HEY) = ar(EYT) now, in AHET, diagonal EY bisects the line segment HT and also the AHET,
∴ar(AHOE) = ar(AEOT)
Similarly in AETY
ar(ΔΕΟΤ) = ar(ΔΤΟΥ)
And in AHTY,
ar(ATOY) = ar(AHOY)
That means diagonals in parallelogram divides it into four equal parts.
Hence Proofed.
Complete question :
la distancia entre la tierra y la luna es de 384 392 km. Los astronautas de la Apolo XL salieron el 16 de julio de 1969 desde el Centro Espacial Kennedy y al alcanzaron la orbita el 19 de julio de 1969. Suponiendo que cada dia recorrieron la misma cantidad de kilometros cuantos kilometros recorrieron por dia
Responder:
128130,66 kilometros
Explicación paso a paso:
Dado que:
Distancia entre la tierra y la luna = 384,392 km
Tiempo empleado = (19 de julio - 16 de julio) mismo año = 3 días
Velocidad = distancia / tiempo
El tiempo empleado es (3 * 24) = 72 horas
Por lo tanto,
velocidad = 384,392 / 72
= 5338,7777 kilómetros por hora
Dado que se supone que la distancia recorrida diariamente es la misma m:
El número de kilómetros recorridos por día:
5338,7777 kilómetros por hora * 24
= 128130,66 kilometros
Answer:
35/100
Step-by-step explanation:
You have to find how many juniors there are, so if you add 13, 20, and 2 you get 35. For the denominator you have to find the total number of students, so just add all of the numbers together to get 100. So there is a 35/100 chance that a randomly selected student is a junior.
Answer:
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
Step-by-step explanation:
we know that
The <u><em>Power of a Power Property</em></u>
, states that :To find a power of a power, multiply the exponents
so
In this problem we have
![9^{\frac{1}{3}} =\sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B9%7D)
Remember that
![\sqrt[3]{9}=9^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Raise to the third power
![[9^{\frac{1}{3}}]^3](https://tex.z-dn.net/?f=%5B9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5D%5E3)
Applying the power of power property
therefore
nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine
