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Vedmedyk [2.9K]
2 years ago
6

Of the 5 factors that should be evaluated when assessing information's quality (Validity, Reliability, Accuracy, Timeliness, and

Bias), which do you think is the most important and why?
Computers and Technology
1 answer:
Art [367]2 years ago
8 0
Validity is the best asseng information to evaluate the all factors
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Idk what the answer choices are
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Java can be procedural or object-oriented when it comes to programming. What is the difference between procedural and OOP?​
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Answer:

Procedural Programming => Functions

Object-Oriented Programming => Classes

Explanation:

Procedural programming is essentially what it sounds like – it's a series of procedures that the computer executes out. A procedure is essentially a function built of different steps that you the coder have grouped as such.

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Hope that helps! And you can always research more online!

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3 years ago
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Compare Fibonacci (recursion vs. bottom up)
ipn [44]

Answer:

C++ code explained below

Explanation:

#include<bits/stdc++.h>

#include <iostream>

using namespace std;

int FiboNR(int n)

{

int max=n+1;

int F[max];

F[0]=0;F[1]=1;

for(int i=2;i<=n;i++)

{

F[i]=F[i-1]+F[i-2];

}

return (F[n]);

}

int FiboR(int n)

{

if(n==0||n==1)

return n;

else

return (FiboR(n-1)+FiboR(n-2));

}

int main()

{

long long int i,f;

double t1,t2;

int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};

cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;

cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;

for(i=0;i<16;i++)

{

clock_t begin = clock();

f=FiboR(n[i]);

clock_t end = clock();

t1=double(end-begin); // elapsed time in milli secons

begin = clock();

f=FiboNR(n[i]);

end = clock();

t2=double(end-begin);

cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds

}

return 0;

}

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If given the chance to own manage a business,what will be the name of the business?
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