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Savatey [412]
3 years ago
8

The roots of x2 − ( ) + 34 are 5 ± 3i.

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0
Use quadratic formula
if you had ax^2+bx+c=0, then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
a=1
b=?
c=34
subsitute
\frac{-b+/- \sqrt{b^{2}-4(1)(34)} }{2(1)}=5+/-3i
\frac{-b+/- \sqrt{b^{2}-136} }{2}=5+/-3i
make 5+/-3 into fraction over 2,(10+/-6i)/2
\frac{-b+/- \sqrt{b^{2}-136} }{2}=(10+/-6i)/2
multiply both sides by 2
-b+/- \sqrt{b^{2}-136}=10+/-6i
we conclude that -b=10
b=-10

ok so equaton is
x^2-10x+34


Mashutka [201]3 years ago
5 0

The roots of  x² -bx+34=0  are 5 ± 3i.  Then b = ?

-------------------

Vieta's formulas :

5 - 3i + 5 + 3i = b <span>⇒ b =10 </span>

Now, we have the equation:

<span>x² -10x + 34 = 0 </span>






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