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goldfiish [28.3K]
2 years ago
15

Two airplanes leave the airport. Plane A departs at a 44° angle from the runway, and plane B departs at a 40° angle from the run

way. Which plane has a larger horizontal distance from the airport when its altitude is 22 miles? Round the solutions to the nearest hundredth. (1 point)
Plane A because it was 22.78 miles away

Plane B because it was 34.23 miles away

Plane A because it was 31.67 miles away

Plane B because it was 26.22 miles away
Mathematics
1 answer:
7nadin3 [17]2 years ago
5 0
I think it’s the 3rd one?
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How is x+3 the same as x over 3​
Lady bird [3.3K]

Answer: I don’t think they’re the same. X over 3 is a fraction, where as x+3 is a problem you would have to solve! I’m not sure if even my answers is correct, if it is not i am sorry abt that, it’s probably bc I suck at math, hence that is why I’m using this site as well

Step-by-step explanation:

8 0
3 years ago
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The girls in Lana’s troop set a goal to sell 1,000 boxes of cookies this year. There are 13 girls in the troop. At least how man
Tomtit [17]

Answer:

77 boxes

Step-by-step explanation:

Take the total number of boxes and divide by the number of girls

1000 boxes / 13 girls

76.92307692

Round up

77 boxes

Check

77*13 = 1001 boxes

6 0
3 years ago
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Find the slope of the surface in the x and y-directions at the given point. h(x,y) = x2 – y2 (-3, 2, 5)
belka [17]
If h(x,y)=x^2-y^2, then you can find partial derivatives: 
\frac{dh}{dx} =2x  \\  \frac{dh}{dy} =-2y.

At point A(-3,2,5) (this is the point which lies on the surface, because 5=(-3)^2-2^2=9-4=5) these derivatives have values:

\frac{dh}{dx} |_A=2\cdot (-3)=-6 \\  \frac{dh}{dy} =-2\cdot 2=-4 -- the slopes at x and y- directions, respectively.



8 0
3 years ago
What is the value of x in the equation 2.5 (6x-4h=10 +4(1.5 + 0.5x)
Komok [63]

Answer:

In this equation x is equal to h + 1

Step-by-step explanation:

To solve this, follow the order of operations for solving equations.

(6x-4h) = 10 + 4(1.5 + 0.5x) ----> Distribute the 4

(6x - 4h) = 10 - 6 + 2x ----> Simplify

6x - 4h = 4 + 2x ----> Subtract 4 from both sides

6x - 4h - 4 = 2x ----->Subtract 6x from both sides

-4h - 4 = -4x ----> Divide by -4

h + 1 = x

3 0
3 years ago
What are the last three terms of the binomial expansion 32x³ + 80x'y + 80x³y² +
Gnesinka [82]

The last three terms of the given binomial expansion are 40x²y³ + 10xy⁴ + y⁵

<h3>Binomial expansion</h3>

From the question, we are to determine the last three terms of the binomial expansion 32x⁵ + 80x⁴y + 80x³y² + __ + __ + __

The highest power of the expansion is 5

Using the binomial expansion theorem

(m +n)⁵ = m⁵ + 5m⁴n + 10m³n² + 10m²n³ + 5mn⁴ + n⁵

Now, we will determine the values of m and n by comparison

By comparison,

m⁵ = 32x⁵

m⁵ = (2x)⁵

∴ m = 2x

Also,

5m⁴n = 80x⁴y

Divide both sides by 5, to get

m⁴n = 16x⁴y

Put m = 2x into the equation

(2x)⁴n = 16x⁴y

16x⁴n = 16x⁴y

∴ n = y

Thus, the expression being expanded is (2x + y)⁵

By binomial expansion, the expansion of (2x + y)⁵  is

(2x + y)⁵ = (2x)⁵ + 5(2x)⁴y + 10(2x)³(y)² + 10(2x)²(y)³ + 5(2x)(y)⁴ + y⁵

(2x + y)⁵ = 32x⁵ + (5×16)x⁴y + (10×8)x³(y)² + (10×4)x²(y)³ + (5×2)x(y)⁴ + y⁵

(2x + y)⁵ = 32x⁵ + 80x⁴y + 80x³y² + 40x²y³ + 10xy⁴ + y⁵

Hence, the last three terms of the given binomial expansion are 40x²y³ + 10xy⁴ + y⁵

Learn more on Binomial expansion here: brainly.com/question/13602562

#SPJ1

8 0
2 years ago
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