Blank 1: If y is -5 when x is 2, that means the equation here is y = -2.5x. So, if x is 8, that makes the equation y = -2.5(8), which gives you -20.
Blank 2: If y is 3 when x is 1, the equation will be y = 3x. If x is 2, that will give you y = 3(2), which is 6.
Blank 3: If y is -7 when x is -21, the equation will be x = 3y. If y is 9, that will give you x = 3(9), which is 27.
Blank 4: If y is 5 when x is 4, the equation will be y = 1.25x. If y is 18, that makes the equation 18 = 1.25x, which is 14.4.
I hope this all helped!
I think the answer might be x=24
so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
To find distance, subtract the largest number from smaller
41 - (-7)
41 + 7 = 48
the distance is 48
hope this helps
Answer:
21/40
Step-by-step explanation:
