On the 12th day the Follicle Stimulating Hormone reach its peak concentration.
The Follicle stimulating hormone stimulates the growth of the egg-bearing follicles in the ovaries. The levels of Follicle stimulating hormone vary during the menstrual cycle and are best measured at its peak or baseline level. FSH levels level vary during the menstrual cycle, reaching their peak prior to ovulation. It is best to measure FSH on day three of the period via a blood sample which is called the baseline level. It provides the most accurate predictions of ovarian reserve.
92 would be your answer have a very nice day
Answer:
d. Fluoride becomes incorporated into the crystalline structure of teeth, making them less susceptible to decay
Explanation:
Dental caries results when cariogenic (caries-causing) bacteria metabolize carbohydrates or sugars present in the mouth for their energy needs, producing organic acids as byproducts, thus lowering the pH of the plaque biofilm.
The hydroxyapatite of tooth enamel is composed mainly of phosphate ions (PO₄³⁻) and calcium ions (Ca⁺). Under normal conditions, there is a stable equilibrium between the calcium and phosphate ions in saliva and the crystalline hydroxyapatite. At low pH (acidic conditions), there is a shift in equilibrium resulting in the dissolution of hydroxyapatite from tooth enamel, a process known as demineralization. A reverse process called remineralization (the process of incorporation of minerals in tooth enamel) occurs when the saliva, acting as a buffer elevates pH. When equilibrium is shifted to favor continued demineralization, dental caries results.
However, when fluoride is present in saliva, fluorapatite, rather than hydroxyapatite, forms during the remineralization process as fluoride ions replace hydroxyl groups in the formation of the apatite crystal lattice.
Fluorapatite is less soluble than hydroxyapatite making it more resistant to demineralization, even under conditions of low pH. Thus, fluoride acts as an effective anticaries agent.
Answer:
0%
Explanation:
Normal female genotype = 
Genotype of a man with hemophilia = 
Crossing the two in marriage:
x
Progeny: 
<em>The two sons from the cross have the genotype </em>
<em> and are therefore free from hemophilia.</em>
Hence, the percentage of their sons that will have hemophilia is zero (0).
The answer is E. I have been studying this in biology.
