Help i am confused and im not sure how to answer this

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

Answer:

y=(x-4)²

Step-by-step explanation:

(a-b)²=a²-2ab+b²

(x-4)²=x²-2×x×4+4²

(x-4)²=x²-8x+16

lakkis [162]3 years ago

7 0

Answer:

y=(x-4)²+1.

Step-by-step explanation:

1) if to re-write the given equation y=x²-8x+C, then 'No Roots' is possible, if C>16;

2) among the given answers the only has 'No roots', it is y=(x-4)²+1, in it C=17.

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(x^2-4x)^2+7x^2-28x+12=0

Valentin [98]

Answer:

$x^4-9x^2-28x=-12$

Step-by-step explanation:

$(x^2-4x)^2+7x^2-28x+12=0$

$(x^4-16x^2)+7x^2-28x=-12$

$x^4-9x^2-28x=-12$

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Light travels about 180 million kilometers in 10 minutes. How far does it travel in one minute? How far does it travel in one se

astraxan [27]

Answer:

18 million kilometers in one min. and 0.3 million kilometers in one second

Step-by-step explanation:

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3 years ago

Read 2 more answers

A projectile is launched from ground level with a initial velocity of Vo feet per second. Neglecting air resistance, its height

antiseptic1488 [7]

The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.

Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s

The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.

Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s

When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.

Answer: 7 s