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2 years ago

Simplify root 12 over root 3

Mathematics

1 answer:

maksim [4K]2 years ago

6 0

Answer:

√

Step-by-step explanation:

pls mark brainliest if possible

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Find a cofunction with the same value as the given expression. csc 52°

sweet-ann [11.9K]

To find a cofunction with the same value as the expression csc 52*, you would use the formula like this. csc (x) = sec (90-x). So if you use csc(52) that equals sec(90-52). This in turn, equals sec(38). So the answer is B.

5 0

3 years ago

Joshua orders some drinks for himself and some friends. He orders three cappuccinos, two iced teas, two cafe lattes, and an espr

Tju [1.3M]

Answer: 1.23

Explanation: hope this helps

8 0

3 years ago

The musical frequency of notes is decreasing between beat numbers ___ and ___

eduard

The complete question in the attached figure

we have that
between beats 2 and 3----------> (392-261.6)=130.4-------> increases
between beats 3 and 4----------> (392-392)=0-----> <span>it stays with the same value
</span>between beats 4 and 5----------> (444-392)=52--------> increases
between beats 5 and 6----------> (444-444)=0-----> it stays with the same value
between beats 6 and 7----------> (392-444)=-52-------> decreases

the answer is
between beats 6 and 7----------> (392-444)=-52-------> decreases

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B81%20%5Ctimes%208%7D%20" id="TexFormula1" title=" \sqrt{81 \times 8} " alt=" \sqr

laiz [17]

Answer:

Step-by-step explanation:

81 = 9 * 9 = 3 * 3 * 3 *3

8 = 2 * 2 * 2 *2

$\sqrt{81 * 8 } = \sqrt{3*3*3*3*2*2*2}\\\\=3 * 3 * 2 \sqrt{2}\\\\= 18\sqrt{2}$

6 0

3 years ago

If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b

Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0

3 years ago