The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
Read more about products at
brainly.com/question/10873737
#SPJ1
Answer:
The answer is 148.6666667
Step-by-step explanation:
1) Set a linear quation
2) Cross multiply
3) Multiple the right side
4) Divide both side by 15
5) Solve the linear equation
3x+7y=-6 -7x+3y=26 -4x+4y=-32 +4x on both sides and you end up with 4y=-32+4x now divide both sides by 4 and you get y=-8+x then to incorporate that in one of the problems 3x+7(-8+x)=-6 do the distributive property with the 7 into the () and you get 3x-56+7x=-6 now add all common variables and get 10x-56=-6 now add 56 to both sides and you get 10x=50 now divide by 10 on both side and you get x=5 now for getting y to equal a number instead of an equation 3(5)+7y=-6 15+7y=-6 subtract 15 on both sides to get 7y=-21 not divide by 7 on both sides to get y=-3 your answers are y=-3 and x=5
I’m pretty sure you would have to make them equal
1. 3x -10=7x+14
2. Add 10 to both sides
3. 3x=7x+24
4. Subtract the variable ( 7x ) from both sides
5. -4x=24
6. Divide -4/24
I hope I did it right let me know if any errors
