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3 years ago

Find the mean(x) of the first ten prime number and hence show that sigma( x1 - x)= 0

Mathematics

1 answer:

SOVA2 [1]3 years ago

8 0

Please see the attached work. I'm assuming that you're familiar with sigma notation (I can explain it if you need that), and as a reminder, x with the line over it indicates the arithmetic mean.

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2 third times 4 fifths

Leviafan [203]

Answer:

$\frac{8}{15}$

Step-by-step explanation:

2 x 4 = 8

3 x 5 = 15

8/15

6 0

3 years ago

Read 2 more answers

What is the sum of the integers between the square root of 12 and 40?

satela [25.4K]

1.

the closest perfect squares of 12 are 9 and 16,

that is 9<12<16

so
$\sqrt{9}\ \textless \ \sqrt{12}\ \textless \ \sqrt{16}$

$3\ \textless \ \sqrt{12}\ \textless 4$

this means, $\sqrt{12}$ is 3 point something...

2.

similarly

36<40<49

so

$\sqrt{36}\ \textless \ \sqrt{40}\ \textless \ \sqrt{49}$

$6\ \textless \ \sqrt{40}\ \textless \ 7$

which means $\sqrt{40}$ is 6 point something...

3.

<span>the sum of the integers between the square root of 12 and 40 is the sum of 4, 5 and 6, since 4 is the smallest integer after root 12, and 6 the greatest integer to before root of 40.

Answer: 15</span>

8 0

3 years ago

There are 58 students enrolled in an art class. The day before the class begins, 10.3% of the students cancel. How many students

Sidana [21]

First, set up a proportion. 10.3% is the percentage of students who cancelled, but the question is asking for the students who are attending, so let’s use 89.7% to make it easier. The proportion would be x over 58 is equal to 89.7% over 100%. Multiply 58 by 89.7, giving you 5,202.6. Next, take 5,202.6 and divide it by 100. This should give you 52. 026, but it’s best to round this to 52. 52 students actually attend the art class, making this your final answer.

7 0

3 years ago

The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend

spayn [35]

Answer:

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

Step-by-step explanation:

The other addend is determined by subtracting $-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5$ from $10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2$ :

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)$

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5$

$x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

$x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

6 0

3 years ago

2/9 - 1/5 • x write an equivalent expression

Bas_tet [7]

Answer:

1/45

Step-by-step explanation:

6 0

3 years ago