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Alja [10]
3 years ago
14

Tina is saving to buy a notebook computer. She has two options. The first option is to put $200 away initially and save $10 ever

y month. The second option is to put $100 away initially and save $30 every month. After how many months Latina say the same amount using either option? How much would you save with either option?
Mathematics
2 answers:
LiRa [457]3 years ago
6 0
200 + 10m = 100 + 30m
200 - 100 = 30m - 10m
100 = 20m
100/20 = m
5 = m....she will have saved the same amount at 5 months <==

200 + 10(5) = 200 + 50 = 250
100 + 30(5) = 100 + 150 = 250
she would have saved $ 250 <===

Elan Coil [88]3 years ago
4 0
You would save $250 which either option
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Step-by-step explanation:

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step 3. subtract x from 100x : 99x = 48

step 4. x = 48/99 (now add the 2 back in)

step 5. answer: 2-48/99.

4 0
3 years ago
2x+4+9x<br><br> a<br> 11x+4<br> b<br> 11x<br> c<br> 15x<br> d<br> 6x+9
MissTica

Answer:

11x+4

Step-by-step explanation:

2x+4+9x

Combine like terms

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5 0
3 years ago
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Plz help<br><br><br><br> (This is the whole problem it says "one part remaining")
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He invested two unknown amount that add to $1200.
Let the amount invested at 9% be x.
Let the amount invested at 3% be y.

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x + y = 1200           First Equation

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The profit from the 3% part is 0.03y.
The two profits add to $78.
0.09x + 0.03y = 78        Second Equation

We have two equations in two unknowns, so we can solve this problem as a system of equations.

x + y = 1200
0.09x + 0.03y = 78

Multiply the first equation by -0.09 and add to the second equation.

-0.09x - 0.09y = -108
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Divide both sides by -0.06

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Now we substitute 500 into y in the first equation.

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3 years ago
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Answer:

<h2>16+x ≤ 26</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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<h3>let's solve:</h3>

so the first condition is

<h3>the maximum number of students in a classroom is 26</h3>

therefore

26 is our subject

and the second condition is

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it means 16 students have already signed up

let's x be more students

therefore

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