Answer:
65
Step-by-step explanation:
First, order the numbers in order. Then find the "middle numbers" and omit them after you have divided the number set into two equals parts. Then find the median of those number sets and then subtract.
You should get 71-6 at the end which is 65.
A) Growth: f(x) because it is getting larger exponentially due to an integer greater than 1 being raised to an exponent.
b) Decay: g(x) because it is getting smaller exponentially due to an integer less than 1 being raised to an exponent.
c) Have the lead exponent being not equal to 1.
d) Whether or not the number being raised to the exponent is greater than or less than 1.
e) f(x) because it is an exponential growth function, which none of the others are.
Answer:
C) The partial derivatives were not evaluated a the point.
D) The answer is not a linear function.
The correct equation for the tangent plane is
or 
Step-by-step explanation:
The equation of the tangent plane to a surface given by the function
in a given point
can be obtained using:
(1)
where
and
are the partial derivatives of
with respect to
and
respectively and evaluated at the point
.
Therefore we need to find two missing inputs in our problem in order to use equation (1). The
coordinate and the partial derivatives
and
. For
just evaluating in the given function we obtain
and the partial derivatives are:


Now, substituting in (1)

Notice that until this point, we obtain the same equation as the student, however, we have not evaluated the partial derivatives and therefore this is not the equation of the plane and this is not a linear function because it contains the terms (
and
)
For finding the right equation of the tangent plane, let's substitute the values of the partial derivatives evaluated at the given point:

or 
I think that should be "D" or "A"
Answer:
x=-5
-2x + 4 = 14
-4 = 14-4
-2x=10
-2/-2=10/-2=-5
x=-5
Step-by-step explanation: