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svetlana [45]
3 years ago
5

The given line passes through the points and (4, 1).

Mathematics
2 answers:
pashok25 [27]3 years ago
5 0

Answer:

y-3=-2(x+4)

Step-by-step explanation:

<u><em>The complete question is</em></u>

The given line passes through the points (−4, −3) and (4, 1).

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, 3)?

step 1

Find the slope of the given line

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(−4, −3) and (4, 1)

substitute the values

m=\frac{1+3}{4+4}

m=\frac{4}{8}

m=\frac{1}{2}

step 2

Find the slope of the perpendicular line to the given line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

so

m_1*m_2=-1

we have

m_1=\frac{1}{2} ---> slope of the given line

so

m_2=-2 ---> slope of the perpendicular line to the given line

step 2

Find the equation in point slope form

y-y1=m(x-x1)

we have

m=-2

point\ (-4,3)

substitute

y-3=-2(x+4) ----> equation in point slope form

trasher [3.6K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

did the edge quiz

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A rock is thrown at 0 seconds from a height of 6 feet. If the parabola representing the height as a function of time has a verte
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Answer:

The correct option is;

The graph will have a height of 6 feet at 16 seconds

Step-by-step explanation:

The given parameters are;

The start time for throwing the rock = 0 s

The height from which the rock is thrown = 6 ft

The vertex of the parabola = 8 seconds

Given that the vertex is the axis of symmetry, then the time it takes the rock to reach the vertex (8 seconds) from the point (0, 6) will be the same time it takes the rock to reach the point on the other side of the parabola at the same 6 feet which will then have coordinates (8 + 8, 6) or (16, 6) which will be 6 feet in 16 seconds.

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What is the slant height of a square pyramid that has a surface area of 319 square feet and a side length of 11 feet?
Dafna1 [17]

Step-by-step explanation:

Surface area of a square pyramid is the area of the square base plus the area of the four triangles made from the base and the slant height.

SA = s² + 4(sh/2)

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You are told that s = 11 and SA = 319. You can now solve for h:

319 = 11² + 2(11)h

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198 = 22h

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I hope it's helpful!!

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The length of a rectangle is 8 more than the width. The area is 105 square centimeters. Find the length and width of the rectang
sashaice [31]

Answer:

Width =  7 cm

Length = 15 cm

Step-by-step explanation:

Let width = w

Length = w + 8

Area of rectangle = 105 sq. cm

length * breadth = 105

(w + 8)*w = 105

Use distributive property

w² + 8w = 105

w² + 8w - 105 = 0

Sum = 8

Product = -105

Factors = 15 , -7   {15 +(-7) = 8 & 15*(-7) = -105}

w² - 7m + 15m - 105 = 0

w(w - 7) + 15(m - 7) = 0

(w - 7)(w + 15) = 0

Ignore w + 15= 0 as measurements will not be in negative value

w - 7 = 0

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What is the monomial if a square of a monomial is:1 9/16 a12b6
san4es73 [151]

Answer:

1\dfrac{1}{4}a^6b^3

Step-by-step explanation:

A square of a monomial is 1\dfrac{9}{16}a^{12}b^6 that is \dfrac{25}{16}a^{12}b^{6}

Use properties of exponents:

(a^m)^n=a^{mn}\\ \\\dfrac{a^m}{b^m}=\left(\dfrac{a}{b}\right)^m\\ \\a^mb^m=(ab)^m

Note that

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Then

\dfrac{25}{16}a^{12}b^{6}=\left(\dfrac{5}{4}\right)^2\cdot (a^6)^2\cdot (b^{3})^2=\left(\dfrac{5}{4}a^6b^3\right)^2

So, the monomial is

\dfrac{5}{4}a^6b^3=1\dfrac{1}{4}a^6b^3

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