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jekas [21]
2 years ago
14

Each of 5 boys randomly chooses a watch from 12 different styles. What is the probability that at least 2 boys choose the same t

ype of watch?
Answer with explanation gets brainliest.
Mathematics
1 answer:
aleksley [76]2 years ago
7 0

Answer:

Ok. So we have 12 different styles of watches to choose from, so that means that the total number of combinations of styles for 5 boys is 12*12*12*12*12, since each boy has his pick of 12 options.

The way to answer this question is by way of the complementary rule: We want the number of ways that the boys can all have different styles. So the first boy to pick has 12 options available to him, the second boy has 11 options available to him, the 3rd boy has 10 options available to him, so on and so forth.

So the probability that the boys all have different watches is (12*11*10*9*8)/12^5= .3819.

To find the probability that at least two boys have the same style would just be 1 -.3819 = 6181

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The question is in the picture.
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<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

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